E102 - VoVo=10m/s Time 2 =0m/s 100 mPosition (cm) sin...

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Time (s) Position (cm) sin Ө Acceleration (cm/s 2 ) V o =10m/s a=5m/s 2 100 m V o =0m/s a=5m/s 2 DEPARTMENT OF PHYSICS Engr. Bernard Aguirre SY 2010-2011 INTERPRETATION OF RESULTS The experiment revolves on the study of motion without considering the forces that causes or develop the motion. It particularly deals with the motion of a particle in a straight line. To determine experimentally the acceleration due to gravity and to study motion by determining the velocity are the primary objectives of this experiment. Time of travel of the cart in a specific displacement was determined using the cart, picket fence and smart timer. Velocity as a function of time is a vector quantity. Both magnitude and direction are required to define it. On the other hand, we often had mistaken identifying speed as tantamount to velocity, which is only its scalar counterpart. The first part uses a cart which is allowed to travel from one end of the track to another in a horizontal path by releasing the button with spring in it. In getting the velocity, the total displacement of the object is divided to time it occupies to reach that certain distance. Velocities obtained are: 75.76 cm/s, 79.96 cm/s, 77.45 cm/s, 74.89 cm/s and 76.02 cm/s. Velocity is dependent on time and displacement. For every change in displacement, there is also change in time, definitely. Mathematically, in an equation of a line, slope=y/x. By making a position-time graph, we can also determine the velocity using its slope because they are equal. Theoretically, velocity of the cart in the experiment must be constant. On experimental reasons, it is because, constant force is applied to object to move, and tendency would be to give constant velocity. Aside from this, position-time relation is a linear function, thus it must give a constant slope or constant velocity. Although we made mistake, the data is seemed to be correct since it has small difference from each other. Using its average, 76.82ms, its absolute deviation is about 2-3% only. One major source of our error is the differences in the amount of force exerted in pushing/releasing the spring plunger. When we exert great force in pushing it, automatically, the cart will move faster than its original velocity. Aside from this, air resistance contributed the decrease of velocity. In connection with this, one great force that hinders the movement of the track is the air drag. If the track of motion is inclined at an angle θ, the motion is uniformly accelerated. Acceleration
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This note was uploaded on 04/27/2011 for the course PHY 10L taught by Professor Agguire during the Spring '11 term at Mapúa Institute of Technology.

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E102 - VoVo=10m/s Time 2 =0m/s 100 mPosition (cm) sin...

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