Quiz1-5 CHE112P - fittficott‘tfitnttmt 2...

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: fittficott‘tfitnttmt 2 mitflwfietet Reaction) QUIZ NO. 1 14, 908 FfiQBLEg} Sfiflflh‘lfi i. {a} I ' Reaction 1 Qne hundred grams of chlorine gas is ‘mixed With '10 grams of hydrogen gas. Upon ignition by a spark, the reaction; H; + ~7) takes place. Assuming compiete reaction ’ 3. Which is the ‘iimiting and excess reactant? b. What ts the percent excess of the excess reactant? , c. What is the fractional conversion of the excess reactant? Methane and oxygen react in the presence of a catalyst to form fornialdehyde. In _ a paraiiel side reaction, some of- the methane is instead oxidized to carbon dioxide and water. ‘ CH4 + 02 9 HCOH + H20 . (desired) CH4 +292 '9 C02 + ZHzo’ Reaction 2 (undesired) The feed to the reactor contains equimdlar amounts of methane and oxygen. The fractional conversion of methane is 0.95 and, the fractional yield of formaidehyde is; 8.90. Calculate-the :molar composition of the reactor output 7 stream and the fieiectivity of formaldehyde to carbon dioxide production. . Ethanol is; produced commercially by hydration of ethylene: on4 + H20 9» CszOH Some of the product is converted to diethyl ether in the side reaction: 2 CZHSGH a! (cznsho + H20 The feed to the reactor containsethylene, -steam—-and~an "inert-gas. 7A sample of the reactor effluent gas is analyzed and found to contain 43.3% mole ethylene, 2.5% mole ethanol, 0.14% mole ether, 9.3% mole inert, and the/balance water. Calculate the molar composition of the reactor feed, the percentage Conversion of ethylene, the fractional yield 'of' ethanol, and the selectivity of ethanol production to reiative to ether production. CHE CALCULATION 2 QUIZ N0. 2 STOHZHIOMETRY (Moiecuiar and atomic baiance) January 2%, 2000 “ ' ' " -.r"..mn""‘ mm.- ~Mmmmwwm—mmm__m__--m_ SQLVE USING BOTH MQLECMLAR BALANQE itND ATQMEC BALANCE 1. Chlorobenzene (C5H5Cl), is an important solvent and intermediate in the production of many other chemicals, is produced by bubbling chiorine gas through liquid benzene in the presence of ferric chloride catalyst. In an undesired side reaction, the product is further chlorinated to dichlorobenzene, and in third reaction to the dichlorobenzene is chlorinated to trichlorobenzene. The feed to the chlorinath consists of essentially pure benzene and a technical grade of chlorine gag; (98% wt Clg, the balance gaseous impurities with an average molecuiar weight of 25.0). The liquid output from the reactor contains 65.0%) Wt C6H5, 32.00/0 Wt C6H5Cl, 2.50/0 Wt C5H4Cl2, and 0.50/0 Wt gaseous output contains only HCl and the impurities that entered with chiorine. Determine the percentage excess of benzene, fractional conversion of benzene, fractional yield of chlorobenzene, and the mass ratio of the gas feed to the liquid feed. The reactions are: C5H5 + Clz “'39 Cal‘lsCl “l” HCI C6H5Cl "l‘ Clz 9 C5H4Cl2 "i‘ C5H4Cl2 + Clg '9 CIH3C33 1% HQ SDLVE estrus EETHER moons fihtr‘thitfifi 0R inQquéfltiiJ-tia manner: 2. Ethane is chlorinated in a continuous reactor: C2H5 + Clz '1}? '5“ HO Some of the monochloroethane is further chlorinated in an undesired side reaction: C2H5Cl + Clz "‘9‘ + The analysis of the feed shows a ratio of 2:3 for C2H6:Clz. The fractional conversion of the ethane is 0.80 and the fractional yield of monochloroetnane is 0.60. Caiculate the molar composition of the output stream and the selectivity of monochloroethane to dichloroethane production. CHE CALCULATION 2 v Quiz No. 3 STOICfl-lIOMETRY (Recycle and Purging) February 4, 2909 PROBLEM SOLVING 1. d—Glucose and dFructose have the same chemical formula (C6H1205) but different "properties. Glucose is converted to fructose as shown in the figure below, but only 50% is converted on one pass through the converter vessel so that unconverted material is recycled. Calculate the molar ratio of the recycle stream to‘ feed stream to the converter. ‘ w Recycle 80% Glucose 20% Fructose Pure Glucose 100 kmole Pure Fructose *Nr—ra' 2f;Ethylenaisfieatalytiealtybhydrated-taetlwl alcohol,rrbut theyreactionrdoes not go toicompletion in a single pass through the reactor. Therefore, much of the ethylene must be recycled. After the reactor, the water and alcohol are condensed out, and the unreacted ethylene is recycled. The molar ratio of ethylene to water entering the reactor must be 0.6. The conversion of ethylene per pass is 4.2%. Calculate : a. recycle ratio (mole recycle/moi fresh feed) required to give an overall conversion 100% b. molar composition of fresh feed c. molar composition of alcohol-water product. Reaction : C2H4 + H20 ->’C2H50H 3. The fresh feed to the converter in an ammonia plant contains 1.5% inert, 75% hydrogen gas, and 23.5% nitrogen gas. The ammonia formed is absorbed by water so removal of ammonia is substantially complete. The residual gases from the absorber are recycled to the inlet of the converter except for a purge provided in the recycle line. The recycle to purge ratio is 45. The yield is 45 moles of ammonia per 100 moles of fresh feed. On this basis, calculate : a. moles of purge gas b. moles and composition of recycle stream c. moles and composition of mixed feed d. single pass conversion of nitrogen gas e. overall conversion of nitrogen gas Reaction : N2 + 3 H2 9 2 NH3 HINT: Do not include in the material balance the absorbing medium used in the absorber. flfifi’ mgwmmm 2 fiifiifié’. «4% $3" KCHIQME‘E‘RE’ (Mamfias fiaflgflm am flamtsugfifim Fahmaw m, :m%% "mm—m..."me WM...“ lmmmrw1mmfimhmMvw/smeAK—flr-nnmmm MW “Wm... mwmm VII-Wm r mmmmfim manna:«wwwmmmmmmmmzwmmmmwmma WWWW WWW—WNWWMWWM MM‘Q’EPLE QfiGECE {2 5% math} 1. The foiicwing are gaswuis aggég $5: 59?; .gr K8; Naturai cfiwflgfifi _ 7; @5159? _ ':.______L§-_Eg§s3§;m;mi fa fue§ cafimining C, H and 3 55 béfié‘fifi-d with excezss. air. M was are bumefi hm: {flue $33 ifiefficient burner same *Ca‘¥‘bm“1 E5 imrmpz’eteiy bumafi. Wm": is; $18 mmmgi‘fim mar»: figgggvn agifl bags? r .-w_.__,,~_w__m..‘ . . _ , a. CF" ,Hzn,332, N2 , " a: _ 2,6: HZ £01, {I}, WHiZW ...... "W ,,,,,,,,,, m. r ‘ WL- -MMMWWWMQN ,,,,, ______ Sgrzifim h": a: {mama mudbig fur L? mimmais m. The Ems; in weight a? a aimé .. "'1‘"— “'"""I'”:"‘"‘ “m ““““ "-7 """ 'M ””””””””””””””” "M" ‘mrw"_7~" w""’~"""““’"" WWWW “ L§;m§§2§m_m_mifi§’§i .............. -__.__ _____ _ fi-&?1.... _______________ J {mg m 53:5 a’bunaa , ' ‘.-« b" .— 4210 A25" :3 aw r.--__ ._... a,§»i?§%§;§%fiz_i__mnflm _ _- _____________________________ sigma? W...““Lg;EflafiiflmWM.Iiigsfiflfzi-mmmmj {2%. :7. mafia: 33§iffiia 4:, 4,3“?! :1, :i'sxrgira L52":% ............. ELK§§87v':€2_@fim_..m5 3g fig. hofifir $353: is firm} . mm ’fififi mfiafiwéng aai’zaéyiaifi; 215% £235 Hg, 3.6% $344, 23% .. is.me m‘azfi 3?:‘2% N2, image; a?“ wad fan? mmmsafifin rmmmmm at 29% ‘ 1L 2 {93" aim gamma": is": the}. fine is (whim a. (lama? 23%.? $3?" i3. Wham a?" Y 2 w. a 1. . ‘ H misfijbk“: mafia“ 'fi’ze m: us}? ,1 ‘u ~§3€i€h ,, 23%“. i q , . n _ v. . '- 23! but at}? the ifitfé caz‘bfin (Therm; #:33me mmmdda. mama; v- ‘ ' , mflpmafiimz 0f the dry flask gas and the ram a? wig? m 13“ a L fii‘iwatrme és bumflré r "3?? :‘5’? :: {'wfifimm cambusfisn chamber“ “‘3th pamhm: mnmmg {hfmfii‘éfi mafia ‘ , ‘ 53% oxygen? 10.2% carbon diaxide, méamm nfiimgen gag a fl it" égzuiam the maxim emeaaa ah” and the magma; WWW“, yam" ‘C‘. “th‘ mmamzm 03 $33M at. CHE CALCULATION 2 STOIcl-IIOMETRY (Energy Balance on Combustion) QUIZ NO. 5 March 2, 2008 MULTIPLE CHOICE (3 pts each) 1. The negative standard heatof combustion of the fuel based on water vapor as a roduct. a. Higher HV ‘ b. Lower HV c. Sensible d. Latent 2. The temperature that would be attained if the fuel were burned in a combustion chamber and all the energy released went into raising the temperature of the reaction roducts. l a. Endothermic b. Exothermic I c. Adiabatic Flame I d. Specific flame when pure oxygen instead of air is 3. The adiabatic flame temperature 1:7 ed. [_a_. increases b. decreases c. remain constant d. divides _ 4. The lower heating value of €5le is 3245.4 kJ/mole. If AHV of water at 25°C is {151.013 kJ/mgle, what is the higher heatin value of C5H12. ' [3. 2981.3 kJ/mole T b. 3509.5 kJ/mole c. 264.1 kJ/mole d. 4356.2 kJ/mole " "’ ‘5. M66! With‘Ultimate" ana'fysTsTof 25.8% C, 5.1% iii}8.20/0‘0711'50/6'NT1T60/0 sand 7.8% Ash is burned in a power plant boiler furnace. Estimate the heating value of the coal. HHl/(klkgl: 33,801 (C)+ 144,158 H —-o.125 o +9413 5 a. 31646 b. 35468 c. 45689 d. 12564 PROBLEM SOLVING 1. A gaseous fuel containing 1.60 moles of methane and 3.72 moles of ethane is burned with 93.10 moles of air. The fuel enters the furnace at 25°C and 1 atm., the air enters at 200°C and 1 atm. The stack gas leaves the furnace at 800°C and 1 atm and contains 5.32 moles C02, 1.60 moles CO, 7.32 moles 02, 12.24 moles H20 and the balance N2. Calculate the heat (id) transferred from the reactor per cubic meter of fuel gas fed. (R = 0.08205 L-atm/mole-K) (25 pts) 2. Calculate the adiabatic flame temperature for CO gas burned at constant pressure with 100% excess air, when the reactants enter at 100°C and one atm. (30 pts) 3. Calculate the adiabatic flame temperature when hydrogen burns with 400% excess air at 1 atm. The reactants enter at 100°C. (30 pts) ...
View Full Document

This note was uploaded on 04/27/2011 for the course CHM 111P taught by Professor Marquez during the Spring '11 term at Mapúa Institute of Technology.

Page1 / 5

Quiz1-5 CHE112P - fittficott‘tfitnttmt 2...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online