lec37-20110411 - .. _ N rv 3?,299’40 g EMU/h. Z4 0 J —...

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Unformatted text preview: .. _ N rv 3?,299’40 g EMU/h. Z4 0 J — 214:; | _: —— I l A : \ 10—68 Determine the product of inertia of IXHI Z xl‘d ‘ + 4% M L' the beam’s cross-sectional area with respect to the f and f axes. o<' M' CENTROID WWW Kama) Mm) 246W) (Wm) WM? J4 (D 5" £2 50+ 32°- (soxse) (253(2va ammo) 50 9e 2 51> :23 :75 :zg'o’b :62Koo 33'3ng (a \v‘ 100 :2;— Uoo)([oooo) (ZS—)Uooao) 200 so 2;)0 52$ 2/0000 :Ioooooo 323-0000 E [2300 lo(,2§oo 44(05 __ [062300 9g — _: m 5(—— [25.“ '4 __ 3 S00 M : 4; 1 : fig FYI W) WPDNEn/T (3.50; Al, (Aw); awe ((5% Ah ( 1W» (mM’r) (Wm) (M wx) (mm) (mmar) (M4 ) M an Iw ’ :0 to 8—3: S” I w 0 2m ("g—fl +2 '6 000°) -—6 o (:o‘) A E if Ix :Avgb :40 l l m _ :o 2 D w 00 ESTOV‘ST 2—3: t’a 8 fig 35 O {D a : IS— : -— o 'd/“Co‘fl “M ((0) Z ~¥.<(ro‘) Im’ : “XS—XML mwfi ...
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This note was uploaded on 04/27/2011 for the course ENGG 130 taught by Professor Lubell during the Spring '08 term at University of Alberta.

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lec37-20110411 - .. _ N rv 3?,299’40 g EMU/h. Z4 0 J —...

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