{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Assignment3_Solution_S11

Assignment3_Solution_S11 - IE 383 Assignment 3 solution...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
IE 383 Assignment 3 solution Some steps are omitted, but you should show your steps in your homework solutions. Problem 1. a.) This is a minisum problem that utilizes rectilinear distance w/ consideration of travel frequency (weight). We can solve the problem by using median condition method. Sum of W= 131 Sum of W/2 = 65.5 X W Cumulative W 100 35 35 210 24 59 250 15 74 300 19 93 400 38 131 Optimal X coordinate is 250. Y W Cumulative W 150 19 19 180 24 43 200 38 81 300 35 116 400 15 131 Therefore the optimal point is at (250, 200) b.) This is a minisum problem that utilizes straight-line distance w/ consideration of travel frequency (weight). We can solve the problem by using center of gravity method. Total weight=131 X*W Y*W Facility A 3500 10500 Facility B 5040 4320 Facility C 3750 6000 Facility D 5700 2850 Facility E 15200 7600 Sum 33190 31270 X* = Sum(Xi * Wi) / Sum (Wi)= 253.36 Y* = Sum(Yi * Wi) / Sum (Wi)= 238.7 The optimal location is at (253.36, 238.7) c.) This is a minimax per trip problem w/o consideration of travel frequency. Because we are required to solve this problem graphically, we should use diamond method and we can use the following formula to double check our graphical solution.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}