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IE 383
Assignment 3 solution
Some steps are omitted, but you should show your steps in your homework
solutions.
Problem 1.
a.)
This is a minisum problem that utilizes rectilinear distance w/ consideration of travel
frequency (weight). We can solve the problem by using median condition method.
Sum of W=
131
Sum of W/2 =
65.5
X
W
Cumulative W
100
35
35
210
24
59
250
15
74
300
19
93
400
38
131
Optimal X coordinate is 250.
Y
W
Cumulative W
150
19
19
180
24
43
200
38
81
300
35
116
400
15
131
Therefore the optimal point is at (250, 200)
b.) This is a minisum problem that utilizes straightline distance w/ consideration of travel
frequency (weight). We can solve the problem by using center of gravity method.
Total weight=131
X*W
Y*W
Facility A
3500
10500
Facility B
5040
4320
Facility C
3750
6000
Facility D
5700
2850
Facility E
15200
7600
Sum
33190
31270
X* = Sum(Xi * Wi) / Sum (Wi)= 253.36
Y* = Sum(Yi * Wi) / Sum (Wi)= 238.7
The optimal location is at (253.36, 238.7)
c.)
This is a minimax per trip problem w/o consideration of travel frequency. Because we are
required to solve this problem graphically, we should use diamond method and we can
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This note was uploaded on 04/27/2011 for the course IE 383 taught by Professor Yi during the Spring '11 term at Southwestern.
 Spring '11
 Yi

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