SelfTest Exercises 8
SelfTest Exercise 8, Solution 1
a.
2
2
3
y
x
2
2
3
y
x
2
2
3
x
y
2
3(
2)
3
x
y
2
3
6
x
y
b.
1
6
– 2
0
4
y
x
1
6
– 2

4
y
x
1
– 2
6

4
x
y
1
4(– 2
6

)
4
x
y
8
24
1
x
y
SelfTest Exercise 8, Solution 3
a.
2
– 3
6
0
x
y
Convert to slopeintercept form
2
6
3
x
y
Reorder the equation
3
2
6
y
x
Divide both sides by 3,
3
2
6
3
3
3
y
x
2
2
3
y
x
Therefore, the slope is
2
3
and the yintercept is 2.
b.
3
4
– 5
0
x
y
Convert to slopeintercept form
4
–3
5
y
x
Divide both sides by 4,
4
3
5
–
4
4
4
y
x
3
5
4
4
y
x
Therefore, the slope is
3
4
and the yintercept is
5
4
.
SelfTest Exercise 8, Solution 5
3
4
0
y
x
Get the x intercept by assuming y=0,
3(0)
4
0
x
4
0
x
Divide both sides by 4,
0
x
3
4
0
y
x
Get the y intercept by assuming x=0,
3
4(0)
0
y
3
0
y
Divide both sides by 3,
0
x
For the third point,
choosing x = 3,
3
y
+
4
(
3
)
=
0
3
y
=−
12
y
=−
4
Therefore, the points are
(0,0) and (3,4).
SelfTest Exercise 8, Solution 7
3
4
(–3, 5)
m
y
mx
b
3

4
y
x
b
Substitute the point into the equation to solve for b,
3
5

(3)
4
b
9
5
4
b
9
b
5
4
11
b
4
3
11

4
4
y
x
Convert to standard form,
3
11
4
4
x
y
Multiply both sides by 4,
3
4
11
x
y
The equation of the line
is
3
4
11
x
y
.
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 Fall '20
 Equations, YIntercept, Elementary algebra