This preview shows pages 1–3. Sign up to view the full content.
41”
F
R
R
R
L
M
R
M
L
300,000 lb
150,000 lb
150,000 lb
1,537,500 ft
∙
lb
1,537,500 ft
∙
lb
0 lb
150,000 lb
150,000 lb
0 ft
∙
lb
1,537,500 ft
∙
lb
1,537,500 ft
∙
lb
1,537,500 ft
∙
lb
0”
0.00050734”
Section 1
Section 2
6.11”
F
R
M
4”
4”
300,000 lb
300,000 lb
1,200,000 ft
∙
lb
300,000 lb
1,200,000 ft
∙
lb
R
M
10.91”
300,000 lb
1,200,000 ft
∙
lb
300,000 lb
1,200,000 ft
∙
lb
109,990.834 lb
1,200,000 ft
∙
lb
6.110”
0.663”
0.447”
4.000”
71.44°
3.631”
0.447”
1.330”
79.65°
0.663”
4.000”
79.65°
10.35°
79.65°
0.447”
0.439”
0.718”
10.35°
3.631”
79.65°
0.663”
4.000”
1.157”
Process Engineering
In the process analyzed by this report, a load is uniformly applied to an aluminum workpiece measuring
6” x 8” x 0.025”, which is mounted on an elastically deformable rubber pad. The workpiece is centered in
the xdirection on the forming press cross head, but it is placed 4” forward in the ydirection. The load is
assumed to be the nominal maximum press force of 150 tons, or 300,000 pounds.
In order to determine the total deflection of the cross head, two separate scenarios must be considered.
First, the bending of the cross head due to the forces acting on the center of the beam must be calculated.
Second, the twisting of the crosssection of the beam due to the offcenter placement of the load must be
determined.
In order to create a simpler idealization of the location of the load, a concentrated force will be assumed
in this report’s calculations.
Bending
The beam is supported on each end by bolts, which support horizontal forces, vertical forces, and
moments. Therefore, fixed supports will be assumed on either end for calculations. This also makes the
beam statically indeterminate. Because the bolts are located 3” in from the ends of the beam, the fixed
supports are assumed to be 3” in as well. The result is a 6” shorter beam, fixed on both ends, that looks
like the following beam theory model:
After the beam theory model was determined, a loading diagram could be drawn.
The applied vertical force,
F
, is supported on either end by two reactive forces,
R
L
and
R
R
. Two
supporting moments,
M
L
and
M
R
, are also located on both the left and the right ends of the beam. There
are no horizontal forces in this situation.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document F
is known and is 300,000 lb.
Because
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 04/27/2011 for the course IME 430 taught by Professor David during the Spring '11 term at Founders College.
 Spring '11
 David

Click to edit the document details