Process Engineering(2)

Process - 79.65 10.35 79.65 300,000 lb 71.44 F 4 0.447 3.631 150,000 lb 300,000 lblb 6.1100 ftlb RR 300,000F lb 300,0000 lb 0.439 0.447 150,000 lb

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41” F R R R L M R M L 300,000 lb 150,000 lb 150,000 lb 1,537,500 ft lb 1,537,500 ft lb 0 lb -150,000 lb 150,000 lb 0 ft lb 1,537,500 ft lb 1,537,500 ft lb -1,537,500 ft lb 0” 0.00050734” Section 1 Section 2 6.11” F R M 4” 4” 300,000 lb 300,000 lb 1,200,000 ft lb 300,000 lb 1,200,000 ft lb R M 10.91” 300,000 lb 1,200,000 ft lb 300,000 lb 1,200,000 ft lb 109,990.834 lb 1,200,000 ft lb 6.110” 0.663” 0.447” 4.000” 71.44° 3.631” 0.447” 1.330” 79.65° 0.663” 4.000” 79.65° 10.35° 79.65° 0.447” 0.439” 0.718” 10.35° 3.631” 79.65° 0.663” 4.000” 1.157” Process Engineering In the process analyzed by this report, a load is uniformly applied to an aluminum workpiece measuring 6” x 8” x 0.025”, which is mounted on an elastically deformable rubber pad. The workpiece is centered in the x-direction on the forming press cross head, but it is placed 4” forward in the y-direction. The load is assumed to be the nominal maximum press force of 150 tons, or 300,000 pounds. In order to determine the total deflection of the cross head, two separate scenarios must be considered. First, the bending of the cross head due to the forces acting on the center of the beam must be calculated. Second, the twisting of the cross-section of the beam due to the off-center placement of the load must be determined. In order to create a simpler idealization of the location of the load, a concentrated force will be assumed in this report’s calculations. Bending The beam is supported on each end by bolts, which support horizontal forces, vertical forces, and moments. Therefore, fixed supports will be assumed on either end for calculations. This also makes the beam statically indeterminate. Because the bolts are located 3” in from the ends of the beam, the fixed supports are assumed to be 3” in as well. The result is a 6” shorter beam, fixed on both ends, that looks like the following beam theory model: After the beam theory model was determined, a loading diagram could be drawn. The applied vertical force, F , is supported on either end by two reactive forces, R L and R R . Two supporting moments, M L and M R , are also located on both the left and the right ends of the beam. There are no horizontal forces in this situation.
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F is known and is 300,000 lb. Because
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This note was uploaded on 04/27/2011 for the course IME 430 taught by Professor David during the Spring '11 term at Founders College.

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Process - 79.65 10.35 79.65 300,000 lb 71.44 F 4 0.447 3.631 150,000 lb 300,000 lblb 6.1100 ftlb RR 300,000F lb 300,0000 lb 0.439 0.447 150,000 lb

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