Ex2_F03_with_solutions

Ex2_F03_with_solutions - Exam 2 Physigsj'zaéil November 1...

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Unformatted text preview: Exam 2 . . __ . Physigsj'zaéil . November 1. Please print yourname onthetop edgeofthe op-scsn sheet. SsIUm“ ‘ Can‘tfifi" 2. Use a #2 pencil to fill in your full name. your student identification number, your recitation division number, and finally the answers for problems 1—12. 3. One (both sides) 3 112" x 11“ one sheet is allowed. It must he hand-written. Usefiil equations and constants: slimy—W3" Jfi-fi=fl.fm qusxfi F=f§xfi s=sxfi p=NiA £=”°"‘= ds=-Bvdf N¢,=L: E 211:! .. d9 d¢ i! ‘5" m 3 d! at HE =_;_CV2 V=£fl_e~rue} =%e+use q=qfle use 1 - s _ 1 mint V=s(1—e M) =Ec e M) me: E , i 1 R‘ 1 m = Efl=iflz z: R1+(XL_XC)1 XL=fl1L XE=E main—i—EX 'X "=1 3-? met hi 3-? R 2 Z poo 2 ' . C1 p0 =4srx10" T-mi'A so =8.85x10'" 2 Ntm e=1.6x10'“c mP=L67>t1lTflkg Mammal“ manomm" “mama-n Fat-MA 13 pages total 1 A circuit for charging a capacth is shown below. The awitch is thmwn to position A at H). The circuit has BIEIIIEHIS a=12V, R=lflfl fl and C=IUflF. How long does it take for the capacitor to ha chargad to 99.9 percant afita final charga'? EfiflMR—L [:29 aim-32 on mpqrutm‘ La fit-1' L¢+ {:1th than}! on :upucmar L: f": C at: w t «r w u -I- I, is; 3m - =7 w as w = we * “Fr-J (a) m3 tYuwHflpl 4-wa- $115] Hf”? a caracl‘hflf‘ a) = I“ E-tXT¢ é a'tm - :—,qq°f=,aul 3; H4711: In LON) =9 1; : _ an Int-am) = —Rr.ln(.nol) r'e'r. = '(m £2)(tano“F) “two = . a? [E 13 pages total 2 A particle of unknown :11ng q and unhicam mass m moves at a speed F4.8><106 mfa in the +x-direetien inte a region cf'eenstant magnetic field. The field has magnitude B=EL5 T and is orientated in the +y~directicn. The particle is deflected in the 42- direetien and traces cut a fragment of a circle of radius R=i}.ln1. What is the sign of the charge and what is its ratio of grin? {a} Neutral, qu=D A d!- .. A -B-- {h} Nasafivejqufifixm-BCIKE JUNE lama-H m ft?! in F I it”; {c} Positive, q!m=1.4x10’3C!Kg 1? m“ 9'” "'1: In“' " 2 mm In M {a} Negative, qhn=9.fixli}"' (3ng - "‘ n = ? {53' Far 1: urfitle mom «1* mum? {e} Poalttve,qu 9.6x10 (3ng {feed f; m it ML} of Mm El 1' a teamreral fitte’ahd‘i‘lflh It '1‘: 1)" This 1].: manure“! 'Forlc" 1i FL: Mac: mug“ . R ._.. The eel; {one antic) on 'Ile. refit]: a 1L me "he. farm F in “"5 mast- Inav'fi _- ' -- f B) 5:: [FBI-.- I1unfllf'131‘F’: WEE-Jim $9- milr“ w B ' T1“ :1, I a; fl .. I * Er= t' 3“ "a ' e R 7W3 "P m “ as t: m](.5T} “ loom”! 13 pages total 3 A leap of wire carrying :1 went has a magnetic dipole moment y. =5x10’4 A-mz. Itfitially, the vector pt makes an angle effifl” with a [1.5 T magnetic. field. As it turns te heeeme aligned with the field, the work done by the field is: 3 ft}!- h “I E. I-‘l‘I g u 'I'I'IH I'lfi'HL J; I; It]. "I u n"; hfhr, £9 h Ir 'l'l y 1 Pa .1 3 A F “I!” E u! a Eur:de i1: my}! 9 ktwnn M and B It Uffl}=-Faifi= - eel E (c) 4.5mm] eu - LLF- ut. = utw- my): (a 4135313“) - (‘413 w JP»? fl {1 1.0Xlfl'4l F, ' E E3; 4.0).:1041 Let hinge” he 111: Hart Jun k1§incui W =fiKE=‘flPE=-fiu=" {-“B)=#B 529'“ 1‘ ’\ ‘= {Ella-tr fl~in‘)(.5 T): NHL- EJHE'HL Co “flrw‘huu 5F “a?! “WWII; 9197/: dkfidfigga 5"? E 13 pages tetal 4 Calculate the magnitude of the magnetic field at the point C=(fl,fl) for the current loop show below. The loop eonsiete of tore straight portions and a eireular are of radius R, which euhtends an angle fl=11f2 at the center of the are. Ignore the contribution of the current in the short ares near the origin (Ml). Ne coma-livva +n E-{Ielcl #1" C clue +9 «H5 do“ '15on Jule-:11; maul or am; 'From C103. ®,51me (if: F :0 ‘1 “IF E Etfl-Squlr'l' Lit-F D 5 IE: 4:51 em .5 r “I? Mr I” ‘ D .,. I - q J ' i - i fi i - --F C x {a} Hammett} Only an Ci) camel-M +v '34:“ a" f (b) Home) . "I I n {e} B=MtBRJ A? 45.1.; wield?! “a?” (:1) Batman) (e) Emma) 13 pages total 5 Two parallel infinite wires ItI cm apart carry currents cf 2A and 4A tresptcctivelyr in the same direction. The force per unit length in Him cf one wire on the ether is: \ “we- (a / WWI (I) l _ . g. 6. “a {a} 1 x1fl‘3 Ntttt tepulstve 11" r ‘1 t-—-—t *- (b) lxlfl‘3 term attractive l J / (c) 4x 10'5 Nfrn repulsive \ / {cl} 4xlfl'5 Nt'm attractive "t a“ .__ ...-r" (e) Ncne cf these u i Lek-ii 1,: q sec-Hen 9i: wire In fit: same Ditfll‘l‘m’l “1 1"" wwcnit fl.” semen It“ icv‘hlt Iflfif, Tine Fat-ts cut via: tunes I5 EHIEHFB‘. Slut-c T PM” cut oi +1.1 pure anti tit: E-ielJ Justu- mrc (D Peru“ «intent tn Ilse Pallf’flh a": we @1 in? ram“ {to 11¢ flying se a: $1313. Pom-n “HI tile. “'71.? anal Lame +iut {am t5fl'l'l'1‘src'l‘WE. IE]:- fflfggi= £1 Irv. .3. mill}? “’5': # 1N attains W I" n F uni, it; ~ ' '1Il‘ 2t Ft: mutt! 4 cs! F in t H? _ I .L: - _ ‘IFKM L2 mats) r5 N ‘5? if :l‘dt " 1 t Q—slfl Tn J, 2“- lL-u‘ n‘H‘qufl'fl'fi 13 pages total 6 A long straight wire {radius 11- 3mm) carries a constant current distributed uniformly over a cross section perpendicular to the axis of the wire. If the current density is j===lIllllil'llll'rn2 in the —s direction, what is the magnitude and direction of the magnetic field B at the point P located 2 mm from the axis of the wire along the x-axis? (Note that the +2 axis points out of the page). F? Define an grocer-Inn leaf C. Forum] flat”. I the ran-Ir of" WI'HLL we want? 7'9 “my”: F3 t'm leer I...“ I‘m . Molt“ Patron. 3" (a) 2x lfl" T in the +y-direction (b) 2x111?3 T in the —3r-dircction {c} l.3:~<lt:r1r T in the +y~direction (d) 1.3xltlt'1f T in the —y—direction T L (e) None of these :- tta-nan!“ Eht‘mJ I-L: “fin-“fly. I} rim, =j (ares elitism. 3mm“ Inf) . "1. I‘ = J11?“ Bf Hmperéi L'W "" - ' ~ :3“ [Qt-cl ties = “(E = tar“ ' 1 ‘—-w--" a, Bus-Mar: “‘st , u o em: flail?" - {a}: = lam!!!” WNW 5-.“ Karl's) B or!“ '- 1- 1 It. inmate arsenal C W TL: Jtricfl‘fl'fl 5': it“ P H ‘Ffifll’l’ y u “710-1th “.19.. It‘ll" For” Jun} u. Jlmtlen oi current [into first), tile-1 Fiver} curl [a direction dF in Particular-1 the. E‘ni“ Punt! Jot-tr- (I.E_ in 1:11 'y dlflc'hnn) d? P. M13 13 pages total 'l' Two long solenoids (radii 2t] mm and 3t] mm respectively} entry the earne current I, flowing in opposite directions. The smaller solenoid is mounted inside the larger, along a common axle. It is observed that there is a zero magnetic field within the inner solenoid. Therefore the inner solenoid must have X times as many turns per unit length on the outer solenoid, where X is: Let‘ the outer toleneltl Lave: curronf if +urn5 n (a) 1 ""“"‘lfll ' (b) 4!? end lat 1'ch ll‘l'flflr‘ “Ln'lJ limit: cur-In“? Ill (a) 233 ’ e 3:: Kim” n‘ e T l‘“ “tilde the Inner solenoid; «the Fired... clue“- +l'¢ "l" solenoids Illfl. B.=u.i,h, H ignorant The met qunem {acid It here line, when: .1 u- . llall=lBll J Le. “ehntlwlhna 2;. entrain—gm e, E cm- 15 are fitted (y eirumrflen 13 pages total 8 A square loop ofwire measuring 12 cm hy12 cm has a battery ofcmf4 V and a lfl Ohm resistor. A uniform magnetic ficld B points out of thc page and is dccrcasing in magnitude at tho ratc of 15!} Tfs . The current in thc circuit is: |, “cinch; “on 1-1:” bile hfll n = flfl a .. R I .4 Ear; 3.41;: awcsw‘ III “HM cheL '77 "'r W =12 om 1 . HE J E “1'? ac= *ch .) = -5!— ca: -cc T ' r at lit: 1 Incitich when? (s) cc: A, clockwise HM“: lmiumJ cui- E“; (b) $.22 A, clockwise W; (o) [LE2 A, counterclockwise I (c) 11.22 A, counterclockwise : c N g (c) {1 A ___._R.... {h Finri cilrec'non a? thfltfiJ curfew} “1M! Loaf; [out if! i- Wfli- “We 33? ‘fiwl‘ J, uni. “Hm Tc c c TL! Elm- e In “can, we mm.- 1'0 Elfin Kc NH Jo Jo L), s E”? cit! n? I“ “if JIM flllrecfifln c5111: erymoi fi‘fie”) 3:22 Riol; languid“ PM" 4mm" in Amman oi imiou E41.” [flu-r J ’1”): cl...“ chm cur} n. «irrerhon a? [mi-:ch curl“!an Lt. ccuofirclocimue. 5 In mum-cm 'ro 11¢ I Haul cufifllfl,fiwro is «im +II£ current Joe 1'0 ‘4! ~ ~ 'I v I Wm»? lccf eruflno‘. t-cfltfl z”) I=E=h=*‘fii 1" Ir counflrdfljmut x " + i. 13 pagcc total 9 mi 11. h- corn-11- = .11 fl) mmcrciccimue + it, filmumnlmmg in n, “chronicle...” '-‘> The figure below shows a circuit that contains tiuee identical mistors with resistance- R = 9 fl , two identical inductors with inductance L = 2J0 M and an ideal batman-3.:r with omfe -13v. What is the current i through tho battery just after the switch is closed? What is the current i through the batter],Ir a long time after the switch has been closed? just After a longtime after (a) 3 A 2 A (b) *5 A 6 A (c) 2 A 2 A (d) 6 A 2 A (13) 2 A 6 A. 7w: ugh:- (uncle. 1; aiIJEJ} CUFFIH+ 1’th “CL l‘flJl-Ithr' ‘5 *Erfl (lltfllfle tflfflh‘i’ fiw hob Imiudw we: fine before trite lair}th m1 fluid, and Ihtiuc‘l'll” Jan‘l- ail'm +Le curmf +1.” film in chef Inmntanfl-Iy). Thu Me an refine eat]. mtiuetor thL an «arm elrculf; 5mm Eiuffaj if, h ink“! ‘ u the current tbru 1L: Shirk-L. “Him? I Ivor ttfllfiohl E..¢:R=a 5w MIML u elem}, turner-1' the: en]. I: conflian “J ,1“!ng (Ly EL='1$)J+L¢ whey! unrest WL Inoioe‘ifl‘l’ a earnJ so we Me; a; will Peffgu “cl. Imlue‘tflr‘ URL 0: Myth “WE-I .._—I-I-—- g-Lflfl e a => t”. “*1 fidfi 3;: 3 a ET leoP larva-hon: E _,E 861:0 £5": L¢E—=3_£:3!IEI!_ R“! #3 R [Q'@ 13pageetotal 10 1G. 1‘7 A long straight wire is in the plane of a rectangular conducting loop. The straight wire carries a constant current 1', as shown below. While the wire is being moved toward the rectangle, the current in the rectangular loop is: his (3) g; mares”? (a) Zero (h) lClockwise (c) CounterclockwiSe (d) Clockwise on the left side and counterclockwise on the right side (e) Counterclockwise on the left side and clockwise on the right side 8)! 1“?qu haul “.33 (LE. Pour}? fhuml m (.lIPQE'l‘l‘On oi: {omen-r} gmjm turl m Jurfichon ol' #1.; E—Elclcl Fom‘I-I mm YLQ Faye w flag rifle oi file wire, Srnre flu: turpo r5 Lem} mama} 11;.me 11c lump 3 the fi-fttlnl m- Hlle Position cl: ‘lrlne “of IS $th Stroyer and "rims +1.6 mu/qmrucle J the majnehe l-luit tullm thelu‘aurlriiliii'flllJ LS muemlhju lens's st the induced turns-11- {rlows m a directrori .50 95 M flpfflje "Mime elaonjfl In Since .5 maturity mil-l: 'Hn'leJ A we. can opyose {LIE Junie weqhemnj 3 “H1 Le wEnlLEHEJ filmle 1):: IHJJOQJ 3-‘Fielcl Pom? In file ofFonhz elrruf’dq 1‘1:- hlie 04*?an E'ficld, he. our is firth By shawl-3r Hill" limit) Mlle [Pallan jlmmt l" J’Wtfm’l HF '“JME'J E'fifulgnjer‘i Wr‘l m rlie ollrer‘lim 15F '"l't thduceol Wfl'r we 'F J 4w L . a” )13 psgdis total l a mural “We” 1“will: 11. Consider hare parallel infinite wins, cne carrying a current cf 5 A cut at” the page, the ether can}ng a current of 5 A late the page. The point P is located such that if a line were drawn from P be each wire, then these lines would subtend an angle ef9fl' degrees, as shown helcw. Furthermore, the point P is at a distance d fi-cm each wire. What is the directicn cf the magnetic field at the point P? 5 A, inte- the page 5 A, cut cf the page {a} UP (b) Down (c) Left (a) Right (e) Intc the page her ninja-ch:- {mini Point-r I a IE 13 pages total 1'2 11 A metal rod is forced to move 1saith constant velocity it along two parallel metal rails, connected with a strip of metal at one end, as shown in the figure below. A magnetic field B - {1.5 T points out of the page. If the rails are separated by L = 212} cm and the speed of the rod is v = 10 cmfs, what is the emf generated? If the rod has a resistance of 5 ohms and the rails and comector have negligible resistance, what is the current I in the red“? I I I I I I I I {a} emf=0fl$ V, Iflflfll A {b} ernf=0.£|2 v.1-o.oo4 A (c) erni'=0.fll V, I=t}.fl A {d} emf=U.DI V, Iflflflm A {e} emfifl V, I-rfl A Let- s- : Jute-ice e? NJ flora Milie- tutti. i. Final manger. {lg}. +Lw leer: EB I“ I §,J]'=1§| [am HIth latest) = 1m Lx * emu. elatiost Ibr- Ll It o-F turns. N1! 1" = -. (.5 The: not.» Mo) = — .0! v ' 3- Moynfl‘vdt oi: mJuceJ current '5 = -_ g M .'.." (IIH’ “I'Ifflflfig R S Q “W hop in LE] 13 pages total 13 ...
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This note was uploaded on 04/27/2011 for the course PHYS 241 taught by Professor Wei during the Spring '08 term at Purdue.

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Ex2_F03_with_solutions - Exam 2 Physigsj'zaéil November 1...

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