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Ex2_S97_with_solutions

Ex2_S97_with_solutions - KEY galuflolfl CflJr'HI*afl...

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Unformatted text preview: KEY galuflolfl - CflJr'HI*afl PHYSICS 241 mm H . ' + April 03,1997 Nnmm__.____..___.___..._m#= W 1. c. - 3.354 x111": OWN -m* 2. n - 3.98% x 10‘ N « m’fC' 3. p. = hr x 10" MA“ . 4. Magnitude of charge on an 01:1:th q. . 1.502 x 10%;? c - 5. Magnitude a! charge on uptown q, I: 1.502 x 10"“ C 6. Mass ufan electron m. - 9.11 at 10““ kg 7. Mass of a. proton In. -1.fiT x lrflks Mm 431:? u. m {. 1|- ' .' cm at) (on J IR’BmMflJ = 13¢“me . 523)); ; :Riglmtmfl) = B trill1L mfwf) " 1. [B points) A. eingly charged ion of meee m1 is nceelereted from reet by I potential difl'erence 1;. it is then deflected by e. uniform magnetic field (perpendicular to the ion'e velocity} into n eernicircle of radio: RI. New I. tripiy-cherged ion of meet in: ie accelerated through the name potential difl’erence end ie deflected by the eeme megnetic field into n eemlcircle ofrediue R: I 231 The retina of theionemeeeeemzfmlie: e: at...“ 1.1“ a, rgJfi, . Nair: .1 4;. A a R.‘ W W“; = 1.5"» “1* 75—5-1;— 18 = J3EE L - am i '24 1” {EM 1 is “in $5.. “11"": _ie. 2 ”11‘4“- “13:3 2 (6 pointe)1‘eroperelleloonductoreeepereted by edietence o I: 30cm. carry currenteinthe'eemedirectiene. Khulflfiiendfg-EEA. Theforeeperi‘l unit length exerted on each conductor by the ether' Le: : :19" B = Hfiil . I.II-—I'I-,,,—.i:JI {AH } at. 4 it 10" film ettrective ' irq : " - Lnn’a' - h L -! ' = _ I‘Fffltl‘L 3| n it”, : 4.2.1.1... (DH } 1. (3 it 10" ani repulsive F I” (E)( l 12 x 10“ ani repulsive -~ "T: e. ir ‘1» -(mm W; .005 A) ma mils M) 5' 1‘ LOX”.- N fim:l'£*lvf e. (5 points] it email airplane with I. wing span of15 m is flying due north at e epeed of 100 rule over e region where the vertical component of the Earth's magnetic field in 1.2 nT. The potential diflerence developed between the wing .Iipfilfli ‘: [(E+fl TEL—*1“ in ”-19.1- 71? A .44 V A H __ .4 ‘ «er-rm w= - ire-JIM remember .i __ Egg ; 3.3:; = “31-“ (95 m&)il.ifw" THU m) {EH 1 1.'5i:l"e'r '-= LB'CIrm'n If I. (Epointe) Thematofwheinthefigurehelowearriuaeurrenteu In 2011!. lnthedhaetionahewnbythearrew. TheradiuoftheareiaRufifiem. The magnetic field at point A k: (AH ) I x 10" T eat of the page 1'! r . ' Edi (EH J a“ x 10" T into the page = I} 3 " fl -'(W*Ia"72(ra AJT' {CH } 2e N_ 19'? T in the plane _ef the page FR- er {.05 In} (D) {a 'x m-i ‘1' ant ofthe page _ I". P. I; ' euro: Tintethe page 5. (3 points) Aeireular hepatwire.efradiuafl=50em,withtweturna1iuin a plane perpendicular to a uniform magnetic field of magnitude .3 = 13.40 T. If in 11.113 a the wire is reshaped into a square with four turns. but remaine in the same plane, what is the magnitude of there ge induced em! (in Volta} in the wire unn'gthietim? ”I ““th d e ' L i mg sf: wenfltlk) - all”? our R .. {An )- awn—anal 5'3"“ 13“” ' " ‘ F'L—‘Jlmflrfiuf “‘5’?“ LE" [B 2'“. -" I". r 1 Eli??? ””er - 1 -1r '“ “ {EH ) stall-#3] M: M; Mae-awn; . marl—ujgg ma}; 4* aw ,hrgLE-ratlnjt’enl 1r. '2 “I!" Eddy) (2 g) 13r(I-%) w: j) Pinyin: Jun Mine}. 6. {8 pointalhhngeohncid10frldiul R, with a number o-fturna per meter macunent which varies.nrithtimeaaI-I.ain(wt). mettle aclenoid andcoudaiwithltiealoolathathuaradiuareRandccnaiataofatotaiof Nturnaoffinewire.'1‘heemfinduccdintheloopiafivenhy: A ~IR’anI,coa{nrt) Bimaf “I ”-Hlunfw‘ij . mtg-Mi. E t EH : H‘HI‘ “h rut] 1-1.1- : awheoafiat) . . 1 [DH } I'R‘n’wf.cca(wi) a“ ' ”£= {NJ-claw «“th jrr (EH ] IPnNarIaith) '3’. (6 points) A 6-1:" battery in used to charge a ED—pF capacitor. The capacitor in then discharged through a 0.34411}! inductor. The maximum current in the circuit 13: ,- Em. CV‘ {Eflflfi-‘K‘ If) a world?" C P the i- ' e ) 2.3a " f5!- {CH 1 m “8‘*F‘-«.1 EE’E % ii: We {fie-ML ‘ Lu! norm" '5 w {- I I '- . R in: Ifwifih aw: r5 '2 30 ”a B. {Bpointe} At t Ii}. aaourceofenifwithEDOV. is applied to acoil that has an inductance of 0.80 H and a resistance of 3G I}. The energy!- atored in the magnetic field when the current reaches half its maximum value is: A (ii ) 33-23 (D)( ) 45.1J R . (nu } aces -- 9. (E pointa] A linuaeidai voltage VG} = [40 V}ain{100t)il applied to I Inlet LCRdrcuitwithL-lfiDmH.C-iflpF.lndR-Bflfl. whammy” betweenthecurrentandtheveltageia: ”Ni“ cut-j“ out ) 495* ¢=+mr (5335)....- (“T‘— _____,r._) lam {Di 53‘ 1‘ m<\h( .4 (I‘tflrflfl ue 'JH)-fl in: 1m —-—--—"—Jr) niwcr" u -5'i-3 (EH ) on “-51.3“ 10. (E pcinte) An RLC circuit in need in a. radic to tune into an FM atatien broad- casting at 99.7 MR2. The refiatance in the circuit is 12 I} and the inductance is 1.4:: pH. What value cf capacitance should be used? - @r-(W‘J’L'r (ri— * UM)“ M (on } 126»? “ ”id-"fir t E ! '_I___.—u— iii“? i 333$ * = We» «Maw; . '1- ' .. “flier-Hm ‘ an" Lmfi}___: 6-” 1c ( H: H ) * “teem-Hi =— 11. (E pcinte) A long straight ccnducting wire cf diameter 4J1 rnnr carries a current of 2D A. Conaidering that the current in unite-maler distributed ever the cylin- drical creel-action cf the 1wire. calculate the magnetic field at a peint Lfl nrnr item the accia of the wire. a J u' I 1: .5;- (DM ) ' 2.00 T IE1 {EH 1 None ofthe above I We: .: :3; E— m- ‘= fiat-Mt: _. . it .1 In“ .11: , “(W :- Jnrle T W): 1.7 {lg-rile} ll} 12. [e palate) Two straight. very long, pereliei conductor: terry current: I; and I; _. inthedlrectioneenhminthefigurebelanfthemegncticfieldntpointC f imbemtheretiooi’thecurrentehflgmnethe: ' 13. {B pointe) An BOO-e? electron traveling along the +2 axis enters I region of uniform magnetic field of magnitudeflflfi‘ T. lithe direction of the magnetic field ie along «4:. determine the magnitude and direction of the electric field neceeeery to keep the electron'moving along it: original direction. A 336x 051.: m {mg-1. can t.“ W = mam-M J ‘_ "" .3'5 '05- — . it '"t‘ I) H’ (03E ; -:.36::I“j VI: 1'? 1L (%§fi;) = Léhuo? rug {DH J 3.35:: mi we _ T _ 5 (EH J 1.72x105fiwm -_ E'th-nxra 'e)(.°1T)-3.'3$~Io .5: 1' 3 L AE=1E ‘EF F;=FE T f ...
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