{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Ex2_Sp06 - Physics 241 Exam#2 This exam consists of 13...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Physics 241 – Exam #2 March 30 2006 This exam consists of 13 problems on 9 pages. Please check that you have them all. Each problem is worth 12 points unless otherwise noted. All of the formulas that you will need are given below. You may also use a calculator. sin θ = y/r cos θ = x/r tan θ = y/x x y r θ e = 1 . 6 × 10 - 19 C k = 9 . 0 × 10 9 N · m 2 / C 2 epsilon1 0 = 8 . 9 × 10 - 12 C 2 / (N · m 2 ) F = kq 1 q 2 r 2 = q 1 q 2 4 πepsilon1 0 r 2 E = kq r 2 Φ = integraldisplay vector E · vector dA = q epsilon1 0 charged plane : E = σ 2 epsilon1 0 V = U E q = - integraldisplay vector E · vector dl dV = - vector E · vector dl point charge : V = kq r U E = q 0 V = kqq 0 r E x = - ∂V ∂x 1 Volt = 1 J / C 1 Volt / m = 1 N / C U E = 1 2 qV C = q V Surface area(sphere) = 4 πR 2 capacitor : U E = 1 2 q 2 C = 1 2 qV = 1 2 CV 2 u E = 1 2 epsilon1 0 E 2 parallel plate capacitor : C = epsilon1 0 A d isolated spherical capacitor : C = 4 πepsilon1 0 R capacitors in parallel : C = C 1 + C 2 + C 3 ... capacitors in series : 1 C = 1 C 1 + 1 C 2 + 1 C 3 ... C = κC 0 I = q t R = V I R = ρ L A V = IR 1
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
P = IV = I 2 R = V 2 R P = E I resistors in series : R = R 1 + R 2 + R 3 ... resistors in parallel : 1 R = 1 R 1 + 1 R 2 + 1 R 3 ... q ( t ) = q 0 e - t/ ( RC ) = q 0 e - t/τ I ( t ) = V R e - t/ ( RC ) = I 0 e - t/τ τ = RC q ( t ) = C E (1 - e - t/ ( RC ) ) = q 0 (1 - e - t/τ ) I ( t ) = E R e - t/ ( RC ) = I 0 e - t/τ vector F B = qvectorv × vector B vector F B = I vector L × vector B vector B = μ 0 4 π qvectorv × ˆ r r 2 Φ B = BA cos θ μ 0 = 4 π × 10 - 7 T · m / A d vector B = μ 0 4 π Id vector lscript × ˆ r r 2 integraldisplay vector B · d vector lscript = μ 0 I B (center of circular loop) = μ 0 I 2 R B (wire) = μ 0 I/ (2 πr ) B (solenoid) = μ 0 nI E = - d Φ B dt U L = 1 2 LI 2 V L = - L dI dt L = μ 0 n 2 Alscript U B = 1 2 μ 0 B 2 ( V ol ) u B = 1 2 μ 0 B 2 I = V R (1 - e ( - t/τ ) ) | V L | = V e ( - t/τ ) τ = L/R ω = 2 πf X C = 1 ωC X L = ωL ω
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern