Coulomb 2-solutions

Coulomb 2-solutions - gilvin(jg47854 2 Coulomb 2...

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F 1 = k (+1) (+1) F 4 = k (+4) (+1) 3 d = 100cm gilvin (jg47854) - 2: Coulomb 2 - meyers - (21235) 1 This print-out should have 9 questions. In order for these forces to be equal, Multiple-choice questions may continue on the next column or page - find all choices before answering. k k This homework is due Thursday,January 27, at midnight Tucson time. 001 10.0 points A charge of +1 Coulomb is place at the 0- cm mark of a meter stick. A charge of −1 r 1 = 4 r 4 r 4 = 4 r 1 = (2 r 1 ) 2 r 4 = 2 r 1 d − r 1 = 2 r 1 r 1 = 1 Coulomb is placed at the 100-cm mark of the same meter stick. Is it possible to place a proton somewhere on the meter stick so that the net force on it due to the two charges is 0? 1. Yes; to the right of the 50-cm mark 2. No correct 3. Yes; to the left of the 50-cm mark Explanation: The proton is repelled from the +1 Coulomb charge and attracted to the −1 Coulomb charge. Both forces act in the same direction so they cannot cancel out. 002 10.0 points A charge of +1 coulomb is place at the 0- cm mark of a meter stick. A charge of +4 coulombs is placed at the 100-cm mark of the same meter stick. Where should a proton be placed on the meter stick so that the net force on it due to the two charges is 0? Correct answer: 33.3333 cm. Explanation: The forces are both repulsive and point in opposite directions. The force due to the +1 charge is 3 = 33.3333 cm 003 10.0 points A charge q 1 of −4.00 × 10 −9 C and a charge q 2 of −2.30 × 10 −9 C are separated by a distance of 40.0 cm. Find the equilibrium position for a third
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Coulomb 2-solutions - gilvin(jg47854 2 Coulomb 2...

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