Coulomb's Law-solutions

Coulomb's Law-solutions - gilvin (jg47854) - 1: Coulombs...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
t = 05.1 C gilvin (jg47854) - 1: Coulomb’s Law - meyers - (21235) 1 This print-out should have 15 questions. Multiple-choice questions may continue on 003 (part 2 of 2) 10.0 points the next column or page - find all choices before answering. This homework is due Tuesday, January 25, at midnight Tucson time. 001 10.0 points You have a neutral balloon. The charge of an electron is −1.6 × 10 −19 C. What is its charge after 12000 electrons have been removed from it? Correct answer: 1.92 × 10 −9 µC. Explanation: The lightning bolt discharge lasts one mil- lisecond. What is the average current flowing from the cloud to ground? Correct answer: 25100 A. Explanation: Let : t = 1 ms = 0.001 s . I = q .001 s = 25100 A . Let : n = 12000 and q e = −1.6 × 10 −19 C . The removal of n electrons leaves a positive charge on the balloon of q = −n × q e = −(12000) (−1.6 × 10 −19 C) × 1 × 10 6 µC 1 C = 1.92 × 10 −9 µC . 002 (part 1 of 2) 10.0 points A strong lightning bolt transfers about 25.1 C to Earth. How many electrons are transferred? The charge on an electron is −1.60218 × 10 −19 C. Correct answer: 1.56662 × 10 20 . Explanation: Let : q = 25.1 C and q e = −1.60218 × 10 −19 C . The charge is proportional to the number of electrons, so q = n |q e | 25.1 C 004 10.0 points Imagine a charge in the middle between two parallel plate conductors. There is no net charge on the plates, and the plates are not connected to ground. q What will happen if the charge is moved a little away from the middle? 1. The charge will move away from the mid- dle. correct 2. The charge will remain stationary. 3. All of these can happen, depending on the size of the charge. 4. The charge will return to the middle. 5. There is not enough information to tell. Explanation: There will be an image-charge attracting it towards each metal surface. The charge will n = q |q e | = |−1.60218 × 10 −19 C| = 1.56662 × 10 20 . move towards the plate closest to it because the image-charge attracting it will be closest and thus stronger.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
gilvin (jg47854) - 1: Coulomb’s Law - meyers - (21235) 2 Any charge (free to move) will go toward the closest conductor it can find. 005 10.0 points Two charges q 1 and q 2 are separated by a distance d and exert a force F on each other. What is the new force F , if charge 1 is increased to q 1 = 5 q 1 , charge 2 is decreased 1.3496.5 N correct 2.4.02599 × 10 34 N · m/C 3.4.12586 × 10 −11 N · m 4. Unable to determine to q 2 = q 2 /2, and the distance is decreased to d = d/2? Choose one 1. F = 25/2 F 2. F = 25 F 3. F = 10 F correct 4. F = 100 F 5. F = 5/4 F 6. F = 20 F 7. F = 50 F 5. None of these 6.4.75067 × 10 20 N/C Explanation: Let : q 1 = q 2 = 46 q p , q p = 1.60 × 10 −19
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 8

Coulomb's Law-solutions - gilvin (jg47854) - 1: Coulombs...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online