# ç¿�é¡�CH3 - E xercises 2 a 24 km h 1 8.7 km h b...

This preview shows pages 1–2. Sign up to view the full content.

Exercises 2. (a) 24 km / h , 18.7 km / h ; (b) 1.75 h 4. (a) Δx = 720 m + 1920 m = 2640 km, so v =2640 m / 180 s = 14.7 m / s; (b) Δx = 720m – 1920m = –1200 m, so v = –6.67 m / s 24. (a) (20 m / s) / 5 s = +4 m / s 2 ; (b) 5 m / s 2 ; (c) 2 s 28. 27 m , 9 m / s 35. (b) 14.3 mph / s ; (c) 8.4 s ; (d) 13 s at 105 mph 36. (a) 5 s, 40 m ; (b) v A = 8 m / s, v B = 16 m / s 38. (a) 6.75 × 10 5 m / s 2 ; (b) 1.33 × 10 . 3 s 47. (a) From Eq. 3.10 : 32 = 48 + 8a, so a = –2 m / s 2 ; (b) v = 12 m / s –(2 m / s 2 ) (4 s) = –4 m / s. 50. (a) v 0 2 = 2gy leads to v 0 = 7.92 m / s ; (b) t = 2v 0 / g = 1.62 s Problems 3. x T = 38 + 20t and x C = 20t + t 2 = x T +11 m. Thus t =7 s and Δx T = 178 –38 = 140 m. 6. (a) Equate x T = 60 + 10t and x C = 30t –2.5 t 2 to find t is not a real number, thus there is no collision. (b) x T = 65 +10t, x C =15 +30t – 1 / 2 at 2 . Set x T = x C to find t is not a real number if a > 4.0 m/s 2 . 9. (a) 25 2 = 15 2 + 2a (100), so a = 2 m / s 2 . v 2 = 25 2 + 2a (100) = 1025, so v = 32 m / s (b) 32 = 25 + 2t, so t =3.5 s

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 05/01/2011 for the course ELECTRIC MAT351 taught by Professor Ahmettantuni during the Spring '10 term at Abant İzzet Baysal University.

### Page1 / 2

ç¿�é¡�CH3 - E xercises 2 a 24 km h 1 8.7 km h b...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online