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Unformatted text preview: Example2.5 : Find the angle between A= 2 i + j + 2 k and B= 4 i  3 j • Cosθ= • = AB B A • 5 3 3 1 4 2 x x x= 1/3 Example2.6: Derive the law of cosines using the scalar product θ cos 2 2 ) ( ) ( 2 2 2 2 2 AB B A C B A B A B A B A C C+ = ⋅+ =⋅= • Example 2.7: Find the vector product of A = 3i 2j + k and B = i+4j –2k k j i j i k j k k j i k j i B A ˆ 14 ˆ 7 ) ˆ 4 ˆ ( ) ˆ 4 ˆ 2 ( ) ˆ 6 ˆ 12 ( ) ˆ 2 ˆ 4 ˆ ( ) ˆ ˆ 2 ˆ 3 ( + =+ + + + =+ × += × Example 2.8: Derive the law of sines using the cross product B A n BC n AC C B C A C C β α sin sin ˆ sin ˆ sin == ×× = ×...
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 Spring '10
 AHMETTANTUNI
 Dot Product, 2J, 1J, 3j, net displacement

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