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Exam 2 Solution

Exam 2 Solution - #1(20 points A(3 pts Problem Assume that...

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Unformatted text preview: #1 (20 points) A) (3 pts) Problem : Assume that a normal person inspires about 6 L/min of bone dry air at 20 º C. Assume that expired air is saturated with warm vapor and is at 37 º C. The molal humidity for saturated water vapor at 37 º C is 6.7%. When saturated, approximately how many grams of water are expired per 1 g of dry air? Solution : Molal humidity = h m = = h m = = 0.067 P i = 0.067P - 0.067P i P i = 0.0628 mol × 18 g/mol = 1.13 g H 2 O P - P i = 1 – 0.0628 = 0.9372 × 28.9 g/mol = 27.09 g air 1.13 g H 2 O/27.09 g air = 0.041 g H 2 O/g air B. (7 pts) Problem : An aqueous solution of urea, (NH 2 ) 2 CO, is found to freeze at -4.6°C at 1 atm pressure. Estimate the boiling point of the same solution at 1 atm. Solution : ∆ T m = T mo – T ms = 0 – (-4.6) = 4.6 ∆ T m = (RT mo 2 / ∆ m H ˆ ) x x = (4.6 × 6009.5)/(8.314 × 273 2 ) = 0.045 ∆ T b = T bo – T bs = (RTb o 2 / ∆ v H ˆ ) x = (8.314 × 373 2 × 0.045)/40,656 = 1.28ºC T bs = 100 + 1.28 = 101.28 ºC = 37.28 K #2 (15 points)...
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Exam 2 Solution - #1(20 points A(3 pts Problem Assume that...

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