Exam 2 Solution - #1 (20 points) A) (3 pts) Problem :...

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Unformatted text preview: #1 (20 points) A) (3 pts) Problem : Assume that a normal person inspires about 6 L/min of bone dry air at 20 C. Assume that expired air is saturated with warm vapor and is at 37 C. The molal humidity for saturated water vapor at 37 C is 6.7%. When saturated, approximately how many grams of water are expired per 1 g of dry air? Solution : Molal humidity = h m = = h m = = 0.067 P i = 0.067P - 0.067P i P i = 0.0628 mol 18 g/mol = 1.13 g H 2 O P - P i = 1 0.0628 = 0.9372 28.9 g/mol = 27.09 g air 1.13 g H 2 O/27.09 g air = 0.041 g H 2 O/g air B. (7 pts) Problem : An aqueous solution of urea, (NH 2 ) 2 CO, is found to freeze at -4.6C at 1 atm pressure. Estimate the boiling point of the same solution at 1 atm. Solution : T m = T mo T ms = 0 (-4.6) = 4.6 T m = (RT mo 2 / m H ) x x = (4.6 6009.5)/(8.314 273 2 ) = 0.045 T b = T bo T bs = (RTb o 2 / v H ) x = (8.314 373 2 0.045)/40,656 = 1.28C T bs = 100 + 1.28 = 101.28 C = 37.28 K #2 (15 points)...
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This note was uploaded on 05/01/2011 for the course CHBE 2100 taught by Professor Staff during the Fall '08 term at Georgia Institute of Technology.

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Exam 2 Solution - #1 (20 points) A) (3 pts) Problem :...

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