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Unformatted text preview: . dt dV − − = Initial volume = 18.5 gal. = 70 L Integration: ∫ ∫ = = = = − = + V 70 V t t t max dt V 0008 . 177 . dV where t max is the time at which the tank will be empty (i.e. V = 0 ). Integrating, we get: s min 344 70 0008 . 177 . 0008 . 177 . ln . 0008 . 1 t max = × + × + − = Since this is less than the required driving time, the student will not make it without stopping. He would require 373344 = 29 mins (0.483 hrs) more, so he would have to stop 0.483x70 = 34 miles short of the destination....
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This note was uploaded on 05/01/2011 for the course CHBE 2100 taught by Professor Staff during the Fall '08 term at Georgia Tech.
 Fall '08
 Staff

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