Take-Home Quiz Solution

Take-Home Quiz Solution - 3 Stage I Heater Artificial...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
1. John empties his bladder after a long morning of working outside. He drinks 24 fl oz. of water, then eats three slices of pizza and drinks two beverages over the next 2 hours. The table below summarizes his consumption. On a splendid day with moderate temperature and low humidity, John perspires at a rate of 0.1 ml/(m 2 · min). Determine the amount of liquid excreted to return John to the state he was at prior to eating and drinking. Assume that the total amount of liquid in his body does not change. Summary of John’s Consumption Product Weight or volume %Water content Water 24 fl oz. 100 Pizza, 3 slices 0.5 kg/slice 20 Coke 8 fl oz. 100 Sprite 4 fl oz. 100 Additional Information: Average area of human skin is 2 m 2 . 1 kg = 35.27 oz 1 oz = 29.57 ml Solution: Simple mass balance In = Out 24 oz + (3 × 0.5 kg × 0.2) + 8 + 4 = [0.1 ml/(m 2 · min) × 2 m 2 ] + X ml 36 + 0.3 kg × 35.27 oz/kg = 0.1 ml/( m 2 · min) × 120 min × 2 m 2 + X ml X = 45.8 oz = 1354 ml
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 3. Stage I Heater Artificial Kidney Dialysate T D1 = 25°C Dialysate T D4 = T D2 = 25°C Waste Dialysate T D2 Waste Dialysate T D3 Dialysate T D5 = 38°C Dirty Blood T B6 = 37°C Clean Blood T B7 = 36.5°C Q 1 Q 2 = 1000 cal/min C = 1 g/m 3 mL/min p = 1 cal/g·°C ρ 00 ௘ ൌ 500 mL/min ܸ ሶ ௕௟௢௢ௗ ൌ ൌ L ܸ ሶ ௗ௜௔௟௬௦௔௧ ݉ ሶ ܸ ሶ ߩ ܪ ሶ = ݉ ሶ ܥ p T Overall balance: (500 mL/min)(1 g/mL)(1 cal/g·°C) (25°C –T D2 ) + (300 mL/min)(1 g/mL)(1 cal/g·°C) (37°C – 36.5°C) + Q 1 = 1000 cal min Î 11650 cal/min – (500 cal/min·°C)T D2 + Q 1 = 0 (1) Kidney: (500 mL/min)(1 g/mL)(1 cal/g·°C) (38°C –T D3 ) + (300 mL/min)(1 g/mL)(1 cal/g·°C) (37°C – 36.5°C) = 1000 cal min Î T D3 = 36.3°C Stage I: (500 mL/min)(1 g/mL)(1 cal/g·°C) (25°C –T D2- T D4 + 36.3°C) = 0 Î T D2 = T D4 Î T D2 = 30.65°C = T D4 Plug into (1) : Î Q1 = 3675 cal/min = 15.4 kJ/min...
View Full Document

{[ snackBarMessage ]}

Page1 / 2

Take-Home Quiz Solution - 3 Stage I Heater Artificial...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online