HW _11 solutions

# HW _11 solutions - 1 x = 0.72642 in = 0.00058 in N = 250...

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1) x = 0.72642 in.; = 0.00058 in.; N = 250 rivet heads 0.99 = x z /2 ( / (N)) = 0.72642 (2.575)(0.00058/ (250)) = 0.72642 9.4457 10 -5 in. 0.98 = x z /2 ( / (N)) = 0.72642 (2.33)(0.00058/ (250)) = 0.72642 8.5470 10 -5 in. 0.95 = x z /2 ( / (N)) = 0.72642 (1.96)(0.00058/ (250)) = 0.72642 7.18975 10 -5 in. 0.90 = x z /2 ( / (N)) = 0.72642 (1.645)(0.00058/ (250)) = 0.72642 6.0343 10 -5 in. 2) Values: 131.15, 130.69, 130.91, 129.54, 129.64, 128.77, 130.72, 128.33, 128.24 129.65, 130.14, 129.29, 128.71, 129.00, 129.39, 130.42, 129.53, 130.12, 129.78, 130.92, 131.15, 130.69, 130.91, 129.54, 129.64, 128.77, 130.72, 128.33, 128.24, 129.65; = 0.05; 1- = 0.95. Hypothesis: = 130 mg x = (1/N) x i = (1/30)(3.8926 10 3 ) = 129.752667 S 2 = (1/(N-1)) (x-x i ) 2 = (1/(30-1))(25.0476) S = (S 2 ) = 0.9294 0.95 = x t /2,N-1

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HW _11 solutions - 1 x = 0.72642 in = 0.00058 in N = 250...

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