Higher Order ODEs - Chapter 08.05 On Solving Higher Order...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Chapter 08.05 On Solving Higher Order Equations for Ordinary Differential Equations After reading this chapter, you should be able to: 1. solve higher order and coupled differential equations , We have learned Eulers and Runge-Kutta methods to solve first order ordinary differential equations of the form ( 29 ( 29 , , y y y x f dx dy = = (1) What do we do to solve simultaneous (coupled) differential equations, or differential equations that are higher than first order? For example an th n order differential equation of the form ( 29 x f y a dx dy a dx y d a dx y d a o n n n n n n = + + + +--- 1 1 1 1 (2) with 1- n initial conditions can be solved by assuming 1 z y = (3.1) 2 1 z dx dz dx dy = = (3.2) 3 2 2 2 z dx dz dx y d = = (3.3) n n n n z dx dz dx y d = =--- 1 1 1 (3.n) ( 29 +--- = =--- x f y a dx dy a dx y d a a dx dz dx y d n n n n n n n 1 1 1 1 1 = ( 29 ( 29 x f z a z a z a a n n n +---- 1 2 1 1 1 (3.n+1) The above Equations from (3.1) to (3.n+1) represent n first order differential equations as follows 08.05.1 08.05.2 Chapter 08.05 ( 29 x z z f z dx dz , , , 2 1 1 2 1 = = (4.1) ( 29 x z z f z dx dz , , , 2 1 2 3 2 = = (4.2) ( 29 ( 29 1 1 2 1 1 x f z a z a z a a dx dz n n n n +--- =- (4.n) Each of the n first order ordinary differential equations are accompanied by one initial condition. These first order ordinary differential equations are simultaneous in nature but can be solved by the methods used for solving first order ordinary differential equations that we have already learned. Example 1 Rewrite the following differential equation as a set of first order differential equations. ( 29 ( 29 7 , 5 , 5 2 3 2 2 = = = + +- y y e y dx dy dx y d x Solution The ordinary differential equation would be rewritten as follows. Assume , z dx dy = Then dx dz dx y d = 2 2 Substituting this in the given second order ordinary differential equation gives x e y z dx dz- = + + 5 2 3 ( 29 y z e dx dz x 5 2 3 1-- =- The set of two simultaneous first order ordinary differential equations complete with the initial conditions then is ( 29 5 , = = y z dx dy ( 29 ( 29...
View Full Document

This note was uploaded on 05/01/2011 for the course CHBE 2120 taught by Professor Gallivan during the Spring '07 term at Georgia Institute of Technology.

Page1 / 8

Higher Order ODEs - Chapter 08.05 On Solving Higher Order...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online