1st and 2nd Rate Order

1st and 2nd Rate Order - [A] o = k 2 t 1/2 t 1/2 = 1 [A] o...

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1st Order Reactions d[A] dt = k 1 [A] 1 [A] d[A] = - k 1 dt ln [A] = - k 1 t + c at t=0 [A] = [A] o boundary condition c = ln [A] o ln [A] = - k 1 t + ln [A] o ln [A] [A] o = - k 1 t [A] = [A] o e -k 1 t A -> B [B] = [A] o - [A] = [A] o ( 1 - e -k 1 t ) 2nd Order Reactions One reactant: d[A] dt = k 2 [A] 2 –1 [A] 2 d[A] = k 2 dt 1 [A] = k 2 t + c [A] t [A] O ln [A] t ln [A] O [A] 1/2 t 1/2 1/[A] t 1/[A] O
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at t=0 [A] = [A] o boundary condition c = 1 [A] o 1 [A] = k 2 t + 1 [A] o 1 [A] - 1 [A] o = k 2 t half-times: [A] = [A] o / 2 1st Order 2nd Order ln [A] o / 2 [A] o = - k 1 t 1/2 1 [A] o / 2 - 1 [A] o = k 2 t 1/2 t 1/2 = ln 2 k 1 = 0.693 k 1 1
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Unformatted text preview: [A] o = k 2 t 1/2 t 1/2 = 1 [A] o k 2 Two Reactants: A + B -> products [A] = a-x [B] = b-x d[A] dt = dx dt d[A] dt = k 2 [A] [B] dx dt = k 2 [a-x] [b-x] dx (a-x)(b-x) = k 2 dt 1 b-a ln b-x a-x = k 2 t + c t = 0 x = 0 boundary condition c = 1 b-a ln b a 1 b-a ln b-x a-x- 1 b-a ln b a = k 2 t 1 b-a ln a(b-x) b(a-x) = k 2 t...
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1st and 2nd Rate Order - [A] o = k 2 t 1/2 t 1/2 = 1 [A] o...

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