problem 18.7

# problem 18.7 - Tanisha Billups = = R= = r0= = U= r 2.65E-10...

This preview shows pages 1–2. Sign up to view the full content.

Tanisha Billups problem 18.7 = ε hcD = 1.51E-23 R = 2^(1/6)r = 297 r0= R*2^(-1/6) = 2.65E-10 U= (4 )*((r0/r)^12-(r0/r)^6)) ε r U 2.65E-10 0 2.66E-10 0 2.67E-10 0 2.68E-10 0 2.69E-10 0 2.70E-10 0 2.71E-10 0 2.72E-10 0 2.73E-10 0 2.74E-10 0 2.75E-10 0 2.76E-10 0 2.77E-10 0 2.78E-10 0 2.79E-10 0 2.80E-10 0 2.81E-10 0 2.82E-10 0 2.83E-10 0 2.84E-10 0 2.85E-10 0 2.86E-10 0 2.87E-10 0 2.88E-10 0 2.89E-10 0 2.90E-10 0 2.91E-10 0 2.92E-10 0 2.93E-10

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

problem 18.7 - Tanisha Billups = = R= = r0= = U= r 2.65E-10...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online