Lesson_2.2_Homework_Solution

Lesson_2.2_Homework_Solution - Lesson 7 Homework Solutions...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
1. What is the acceleration of the system shown on the right if m 1 = 2 kg and m 2 = 4 kg? Consider the forces on m 1 The weight of m 1 = m 1 g = 2 kg × 9.8 ms -2 = 19.6 N acts vertically down on m 1 . The tension T on the string pulls m 1 upward. Assuming that m 1 moves up, the net force on m 1 is T – 19.6. If a is the acceleration of the system, then: F net = m 1 a T – 19.6 = 2a ….(i) Consider the forces on m 2 The weight of m 2 = m 2 g = 4 kg × 9.8 ms -2 = 39.2 N acts vertically down on m 2 . The tension T on the string pulls m 2 upward. Assuming that m 2 moves down, the net force on m 2 is 39.2 – T . Since a is the acceleration of the system: F net = m 2 a 39.2 – T = 4a ….(ii) Adding equations (i) and (ii) gives: 39.2 – 19.6 = 6a a = 3.27 ms -2 Using this value of a in equation (i) we have: T – 19.6 = 2 (3.27) T = 26.14 N 2. The figure on the right, if there is no friction between the inclined plane and 3.0 kg mass, find the acceleration of the masses and the tension on the string. 3 kg 40 o 5 kg 18.9 N T 49 N T 29.4 N Consider the forces on the 3.0-kg mass The weight of the 3-kg mass = 3 × 9.8 = 29.4 N acts vertically down. The component of this down the plane = 29.4 sin 40
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 5

Lesson_2.2_Homework_Solution - Lesson 7 Homework Solutions...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online