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Lesson_2.2_Homework_Solution

# Lesson_2.2_Homework_Solution - Lesson 7 Homework Solutions...

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1. What is the acceleration of the system shown on the right if m 1 = 2 kg and m 2 = 4 kg? Consider the forces on m 1 The weight of m 1 = m 1 g = 2 kg × 9.8 ms -2 = 19.6 N acts vertically down on m 1 . The tension T on the string pulls m 1 upward. Assuming that m 1 moves up, the net force on m 1 is T – 19.6. If a is the acceleration of the system, then: F net = m 1 a T – 19.6 = 2a ….(i) Consider the forces on m 2 The weight of m 2 = m 2 g = 4 kg × 9.8 ms -2 = 39.2 N acts vertically down on m 2 . The tension T on the string pulls m 2 upward. Assuming that m 2 moves down, the net force on m 2 is 39.2 – T . Since a is the acceleration of the system: F net = m 2 a 39.2 – T = 4a ….(ii) Adding equations (i) and (ii) gives: 39.2 – 19.6 = 6a a = 3.27 ms -2 Using this value of a in equation (i) we have: T – 19.6 = 2 (3.27) T = 26.14 N 2. The figure on the right, if there is no friction between the inclined plane and 3.0 kg mass, find the acceleration of the masses and the tension on the string. 3 kg 40 o 5 kg 18.9 N T 49 N T 29.4 N Consider the forces on the 3.0-kg mass The weight of the 3-kg mass = 3 × 9.8 = 29.4 N acts vertically down. The component of this down the plane = 29.4 sin 40

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Lesson_2.2_Homework_Solution - Lesson 7 Homework Solutions...

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