This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Lesson 5.1 Homework Solutions 1. Total mass M = 1280 kg, the mass of the ma m = 80, x = 0.014 m The force compressing the spring = mg = 80 9.8 = 784 N 4 1 4 784 5.6 10 0.014 5.6 10 6.61 1280 6.61 1.1 2 2 F k N m x k Hz M f Hz  = = = = = = = = = 2. m = 1.5 kg, k = 200 N.m1 , x(0) = 0.1 m and v(0) = 2.0 ms1 . (i) 200 11.6 1.5 k Hz m = = = The position of the vibrating mass can be written as x(t) = A cos( t + ) 0.1 = A cos (i) v(t) = x(t) = A sin( t + ) 2 = 11.6A sin (ii) Dividing (ii) by (i) gives: 2 tan 0.1 11.6 = , or, = 1.05 rad From (i) above, 0.1 0.2 cos( 1.05) A m = = The position function is x(t) = 0.2 cos(11.6t 1.05) (ii) 2 2 0.54 11.6 T s = = = (iii) v max =  A =  0.201 11.6 = 2.3 ms1 . Amax =  A 2 =  0.201 11.6 2 = 26.8 ms2 . (iv) 3. A = 0.5 m, = 6 rad s1 , = /6 rad (i) 3 2 3 2 1 6 1 f T z s f H = = = = = (ii) 2 1 2 , 0.5 (6 177.7 ) k k m m Nm...
View
Full
Document
 Fall '10
 George
 Physics, Force, Mass, Work

Click to edit the document details