Lesson_5.2_Homework_Solution

Lesson_5.2_Homework_Solution - Lesson 5.2 Homework...

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Lesson 5.2 Homework Solutions 1. (i) λ = 0.8 m (ii) T = 1/f = ½ = 0.5 s (iii) v = f λ = 2 x 0.8 = 1.6 ms -1 . (iv) Number of waves = x/ λ = 2.4/0.8 = 3 (v) (a) 0, (b) 0, (c) π , (d) π /2 (vi) Transverse. The direction of vibration of particles is perpendicular to the direction of propagation of the wave. 2. (i) f = 2.5 Hz 1 1 2.5 0.4 T f s = = = (ii) v = x/t = 5/2.5 = 2 ms -1 . (iii) λ = v/f = 2/2,5 = 0.8 m (iv) Number of waves = x/ λ = 5/0.8 = 6.25 (v) Phase difference between points 0.8 m apart = 0 (vi) Phase difference between points 4.0 m apart = 4 2 1 8 0 0. π × = . This is the same as a phase difference of zero since it is a multiple of 2 π . (vii) This is a transverse wave. 3. (i) v = x/t = 500/1.3 = 333.3 ms -1 . (ii) f = 50 Hz . (iii) λ = v/f = 333.5/50 = 6.67 m (iv) Number of waves = x/ λ = 500/6.67 = 75 (v) Longitudinal as the direction of propagation of the wave is the same as the direction of vibration of the particles. 4. v = 25 ms -1 , x = 8.2 m, m = 0.22 kg.
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This note was uploaded on 05/01/2011 for the course PHY 2048 taught by Professor George during the Fall '10 term at Edison State College.

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Lesson_5.2_Homework_Solution - Lesson 5.2 Homework...

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