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Unformatted text preview: Lesson 5.3 Homework Solutions 1. (i) This wave pulse advances to the right with a speed of 5 ms1 . Its velocity is 5 i . (ii) 0.07 m 5.0 m The figure shows how the pulse advances with time. The distance between successive maxima is 5 m indicating that the wave is moving to the right at 5 ms1 . (iii) The maximum displacement occurs when the term x 5t = 0. The maximum displacement = 0.07 m and this is the amplitude of the wave pulse. (iv) The wave pulses are the same as before, but they are advancing to the left with a speed of 5 ms1 . Its velocity is 5 i . 2. f = 5 Hz, v = 10 m.s1 , = v/f = 10/5 = 2.0 m, A = 0.1 m 1 2 2 2 k m  = = = , = 2 f = 10 y(x,t) = A sin(kx t) = A sin {k(x vt)} y(x,t) = 0.1 sin ( x 10 t) = 0.1 sin { (x 10t)} 3. (i) 0.3 m (ii) k = 12.57 m1 . (iii) 2 2 12.57 0.5 m k = = = (iv) Angular frequency = 251 Hz (v) 251 1 1 , 40 0.025 2 2 40 H f T f z s = = = = = = (vi) 1 251 12....
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This note was uploaded on 05/01/2011 for the course PHY 2048 taught by Professor George during the Fall '10 term at Edison State College.
 Fall '10
 George
 Physics, Work

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