Unformatted text preview: t trans &gt; 2 t prop . Now 2 × t prop = 2.304 μ sec &lt; t trans . Hence, collision can be detected. Question 3 Wait for 51,200 bit times. For 10 Mbps, the waiting time is 51200 bits / 10 Mbps = 5.12 msec. For 100 Mbps, the waiting time is 512 μ sec. Question 4 After the first event, there will be one entry in the switch table: (A, 1). The switch will forward the frame through its interfaces 2, 3, and 4. After the second event, there will be two entries in the switch table: (A, 1) and (D, 4). The switch will forward the incoming frame through its interface 1....
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- Spring '11
- Electronics, Harshad number, Byte, Transmitter, switch table