sol8(1) - fragments are 0 60 120 180 240 300 and 360 Each...

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EE3015 Tutorial 8 (Solution) Question 1 125 interfaces require at least 7 bits. 60 interfaces require at least 6 bits. Network addresses are:,, OR,, Question 2 Maximum size of each fragmented datagram in user bytes = 480 (Note: there are 20 bytes in IP header). 7 480 20 3000 = Number of fragments required = Each fragment will have identification number 422. The segment offsets of the
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Unformatted text preview: fragments are 0, 60, 120, 180, 240, 300, and 360. Each fragment except the last one will be of size 500 bytes (incl. 20 bytes of IP header) and will have the More flag equal to 1. Last fragment will be of size 120 bytes (incl. 20 bytes of IP header) and will have the More flag equal to 0. Question 3 NAT will not have an entry for a connection initiated from the WAN side, hence will drop incoming packets from A....
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This note was uploaded on 05/01/2011 for the course ELECTRICAL EE3015 taught by Professor Albertsun during the Spring '11 term at City University of Hong Kong.

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