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Unformatted text preview: (6.2a) (2.17) 1 st Tds equation is in term of du; The 2 nd TdS Equation in terms of dh. Why do we need in term of dh? Closed versus Open System H = U + pV dH = d(U + pV) = dU + d(pV) = (dU + pdV) + Vdp =TdS + Vdp Therefore, TdS = dH Vdp the 2 nd TdS equation Mass basis: Tds = dh vdp In a constant pressure process: Tds = dh e.g., during phase change, ds = (h g h f )/T For an incompressible Substance, apply the 1 st Tds equation: Tds = du = c(T) dT Heating water from ambient cold day (32 o F) to 200 o F : s 1 = 0.0003 Btu/lb. o R s 2 = 0.294 Btu/lb. o R Saturated vapor s g = 1.7762 Btu/lb. o R...
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This note was uploaded on 05/01/2011 for the course ME 200 taught by Professor Gal during the Spring '08 term at Purdue UniversityWest Lafayette.
 Spring '08
 GAL

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