Lec32 - c v and c p Under isentropic assumption from Eq...

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ME 200: Thermodynamics I Lecture 32: Isentropic processes Sections 6.11 Problems: SP32; 6.125, 6.129 Professor Hukam Mongia Office Hours: MWF 2:30 to 3:30 pm in ME 83 (Other times email for appointment) Email: [email protected] Phone: 765-494-5640 Course Website: https://engineering.purdue.edu/ME200 Course Secretaries: Diana Akers (ME 84) and Marilyn Morrison (ME 100) See Kul Inn (ME 189) about grading Homework Assignments 1
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Isentropic Processes Most ideal the best an equipment can be expected to perform. Calculating properties becomes relatively straightforward. Especially if we combine it with the ideal gas law 2
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3 Recall Equations 6.20a, 6.21 and 6.22: With constant
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Unformatted text preview: c v and c p : Under isentropic assumption, from Eq. 6.20a, we can calculate s o ( T 2 ) : 4 Utilize the ideal gas law in addition to s 1 = s 2 , to derive relationship for v 2 / v 1 for air going through an isentropic process: 5 Ideal gas going through isentropic process with constant c v and c p : Then from Equations 6.22b and 6.21 b one gets, respectively: 6 Polytropic Process: P v n = constant Constant Pressure Heat addition at constant volume Diesel engines Constant pressure heat addition Gas turbines 7 Example 6.9 Use A-22E: pr2 = 21.18, pr1 = 1.3860 p2 = 15.281 atm From Table A-20 E K at 850 o R (390 o F) is 1.39 p2 = 15.26 atm....
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