HW 3A solution_pdf

# HW 3A solution_pdf - ghei(mg42382 – HW 3A – opyrchal...

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Unformatted text preview: ghei (mg42382) – HW 3A – opyrchal – (11130) 1 This print-out should have 5 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A particle moving at a velocity of 2 . 3 m / s in the positive x direction is given an accelera- tion of 0 . 1 m / s 2 in the positive y direction for . 5 s. What is the final speed of the particle? Correct answer: 2 . 30054 m / s. Explanation: Let : v xf = v xi = 2 . 3 m / s . a y = 0 . 1 m / s 2 , and t = 0 . 5 s . The vertical velocity undergoes constant ac- celeration: v yf = v yi + a t = 0 + (0 . 1 m / s 2 )(0 . 5 s) = 0 . 05 m / s . Thus v f = radicalBig v 2 xf + v 2 yf = radicalBig (2 . 3 m / s) 2 + (0 . 05 m / s) 2 = 2 . 30054 m / s . 002 10.0 points A fireman, 55 . 6 m away from a burning build- ing, directs a stream jet of water from a ground level fire hose at an angle of 41 . 4 ◦ above the horizontal. The acceleration of gravity is 9 . 8 m / s 2 . If the speed of the stream as it leaves the hose is 46 . 7 m / s, at what height will the stream of water strike the building?...
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## This note was uploaded on 05/02/2011 for the course PHYSICS 111 taught by Professor Wang during the Spring '09 term at NJIT.

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HW 3A solution_pdf - ghei(mg42382 – HW 3A – opyrchal...

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