HW 7 solution_pdf

HW 7 solution_pdf - ghei(mg42382 – HW 7 – opyrchal...

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Unformatted text preview: ghei (mg42382) – HW 7 – opyrchal – (11130) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A child bounces a 45 g superball on the side- walk. The velocity change of the superball is from 23 m / s downward to 14 m / s upward. If the contact time with the sidewalk is 1 800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? Correct answer: 1332 N. Explanation: Let : m = 45 g = 0 . 045 kg , v u = 14 m / s , v d = 23 m / s , and Δ t = 0 . 00125 s Choose the upward direction as positive. The impulse is I = F Δ t = Δ P = mv u- m (- v d ) = m ( v u + v d ) F = m ( v u + v d ) Δ t = (45 g) (14 m / s + 23 m / s) . 00125 s = 1332 N . 002 10.0 points A 86 . 4 kg ice skater, moving at 9 . 1 m / s, crashes into a stationary skater of equal mass. After the collision, the two skaters move as a unit at 4 . 55 m / s. Suppose the average force a skater can experience without breaking a bone is 4632 N. If the impact time is 0 . 103 s, what is the magnitude of the average force each skater experiences? Correct answer: 3816 . 7 N. Explanation: Let : m = 86 . 4 kg , v i = 9 . 1 m / s , v f = 4 . 55 m / s , F = 4632 N , and Δ t = 0 . 103 s . From the impulse-momentum equation, F av Δ t = Δ p = m ( v f- v i ) . F av = m ( v f- v i ) Δ t = (86 . 4 kg) (4 . 55 m / s- 9 . 1 m / s) . 103 s =- 3816 . 7 N , which has a magnitude of 3816 . 7 N . The average force on skater 2 has the same magni- tude but opposite direction by Newton’s third law. This force is not great enough to break a bone. 003 10.0 points A(n) 810 N man stands in the middle of a frozen pond of radius 7 . 9 m. He is un- able to get to the other side because of a lack of friction between his shoes and the ice. To overcome this difficulty, he throws his 1 . 4 kg physics textbook horizontally toward the north shore, at a speed of 7 m / s. The acceleration of gravity is 9 . 81 m / s 2 . How long does it take him to reach the south shore? Correct answer: 66 . 5606 s. Explanation: Let : W m = 810 N , r = 7 . 9 m , m b = 1 . 4 kg , and v ′ b = 7 m / s . The mass of the man is m m = W m g . ghei (mg42382) – HW 7 – opyrchal – (11130) 2 From conservation of momentum, m m v m + m b v b = m m v ′ m + m b v ′ b 0 = m m v ′ m + m b v ′ b v ′ m =- m b m m v ′ b =- g m b W m v ′ b =- ( 9 . 81 m /...
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This note was uploaded on 05/02/2011 for the course PHYSICS 111 taught by Professor Wang during the Spring '09 term at NJIT.

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HW 7 solution_pdf - ghei(mg42382 – HW 7 – opyrchal...

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