# hw09_problem3_yourlogin - m = 1/(6.1082*2.3) = 0.0711 2.3...

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Name(s) : Purdue Email Address(es): Section #: Assignment #: I/We have not used material obtained from any other unauthorized source, or unmodified. Neither have I/we provided access to my/our work to anoth The project I/we am/are submitting is my/our own original work. Problem Description: Input Section: Age of Tree (years) Average Height (in feet) 1 6 2 9.5 3 13 4 15 5 16.5 6 17.5 7 18.5 8 19 9 19.5 10 19.7 11 19.8 Calculation Section: General Form: x = b e^my x = b 10^my m m = 1/6.1082 = 0.1637

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Unformatted text preview: m = 1/(6.1082*2.3) = 0.0711 2.3 is approximate conversion factor between b b = e^(0.1637*6.0993) = 2.714 b = 10^(0.0711*6.0993) = 2.714 x = (2.714) e^(0.1637y) x = (2.714) 10^(0.0711y) either modified her. Output Section: n log base 10 and natural log 1 10 5 10 15 20 25 f(x) = 6.11 ln(x) + 6.1 R² = 0.99 Average Height of Cherry Trees as they Ag Age of Tree (years) Average Height (in feet) 100 ge...
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## This note was uploaded on 05/02/2011 for the course ENGR 132 taught by Professor Kutson during the Spring '11 term at Purdue.

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hw09_problem3_yourlogin - m = 1/(6.1082*2.3) = 0.0711 2.3...

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