Unformatted text preview: Moles of KOH – Moles of Al(OH)3 = Moles of excess hydroxide .05 mol of KOH – .038 mol of Al(OH)3 = .012 mol of excess hydroxide 3) Describe the reaction between Al(OH)3 and OH- using Bronsted terminology. Bronstead Lowry acids are molecules that have an H+ molecule in them that dissociates when in solution. Bronstead Lowry bases are molecules that can accept OH- when in solution and have a lone pair of electrons. Al(OH)3 is BL acid and OH is BL base and the conjugate base of Al(OH)3. OH is added to the Al(OH)3 molecule making Al(OH)4-, this process decreases the amount of OH in solution which decreases the pH, which makes Al(OH)3 the acid and conjugate acid of OH. 5) What is the purpose of suspending the thread in the solution from which crystallization of alum is to take place? This is so that the crystals can have more surface area to form upon and it makes for easy removal of some of the crystals for weighing....
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- Spring '11
- Chemistry, Sodium hydroxide, excess hydroxide