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Unformatted text preview: weight oF the object because it is oating, so the amount oF displaced uid is the same. 003 10.0 points Two identical strings are stretched such that the frst harmonic oF the frst string has the same Frequency as the second harmonic oF the second string. What is the ratio F 1 F 2 oF the tension Force in the frst string to that oF the second string? 1. F 1 F 2 = 8 2. F 1 F 2 = 4 correct Version 019/AABAD QTest #11 Antoniewicz (57420) 2 3. F 1 F 2 = 1 4. F 1 F 2 = 2 5. F 1 F 2 = 1 16 6. F 1 F 2 = 1 4 7. F 1 F 2 = 1 2 8. F 1 F 2 = 1 8 9. F 1 F 2 = 16 10. F 1 F 2 = 2 Explanation: Call the length of both strings L and their mass densities per unit length . The wave speed is v = f = 2 L n f n , where n is an integer and v = r F , where F is the tension in the string, so the tension force is F = v 2 = p 2 L n P 2 f 2 n 1 n and F 1 F 2 = p n 2 n 1 P 2 = p 2 1 P 2 = 4 ....
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This note was uploaded on 05/02/2011 for the course PHY 303K taught by Professor Turner during the Spring '08 term at University of Texas at Austin.
 Spring '08
 Turner
 Physics

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