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Unformatted text preview: weight oF the object because it is ±oating, so the amount oF displaced ±uid is the same. 003 10.0 points Two identical strings are stretched such that the frst harmonic oF the frst string has the same Frequency as the second harmonic oF the second string. What is the ratio F 1 F 2 oF the tension Force in the frst string to that oF the second string? 1. F 1 F 2 = 8 2. F 1 F 2 = 4 correct Version 019/AABAD – QTest #11 – Antoniewicz – (57420) 2 3. F 1 F 2 = 1 4. F 1 F 2 = 2 5. F 1 F 2 = 1 16 6. F 1 F 2 = 1 4 7. F 1 F 2 = 1 2 8. F 1 F 2 = 1 8 9. F 1 F 2 = 16 10. F 1 F 2 = √ 2 Explanation: Call the length of both strings L and their mass densities per unit length μ . The wave speed is v = λ f = 2 L n f n , where n is an integer and v = r F μ , where F is the tension in the string, so the tension force is F = μ v 2 = μ p 2 L n P 2 f 2 n ∝ 1 n and F 1 F 2 = p n 2 n 1 P 2 = p 2 1 P 2 = 4 ....
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 Spring '08
 Turner
 Physics, Buoyancy, Force, Fundamental physics concepts, Version 019/AABAD

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