Traditional Old Midterm 2

Traditional Old Midterm 2 - Version 080 Midterm 02 Yao...

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Unformatted text preview: Version 080 Midterm 02 Yao (58180) 1 This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points In another solar system is planet Driff, which has 5 times the mass of the earth and also 5 times the radius. How does the gravitational acceleration on the surface of Driff compare to the gravita- tional acceleration on the surface of the earth? 1. Its 25 times as great. 2. There is no gravity on Driff because 5 times 4000 miles (the radius of the earth), is 20000 miles, far beyond the pull of gravity. 3. Its 5 times as much. 4. Its 1 5 th as much. correct 5. Its 1 25 th as much. 6. Its the same, 10 m / s 2 . Explanation: Let : M D = 5 M e and R D = 5 R e . Gravitational force is F = mg = G M m r 2 g = GM r 2 M r 2 , so g D g e = m D r 2 D m e r 2 e = M D r 2 e m e r 2 D = (5 m e ) r 2 e m e (5 r e ) 2 = 1 5 g D = 1 5 g e . 002 10.0 points Two satellites A and B, where B has twice the mass of A, orbit the earth in circular orbits. The distance of satellite B from the earths center is twice the distance of satellite A from the earths center. What is the ratio of the orbital period of satellite B to that of satellite A? 1. T B T A = 1 / 8 2. T B T A = 2 3. T B T A = radicalbig 1 / 2 4. T B T A = 2 5. T B T A = 8 correct 6. T B T A = radicalbig 1 / 8 7. T B T A = 1 8. T B T A = 1 / 4 9. T B T A = 1 / 2 10. T B T A = 8 Explanation: According to Keplers third law, the square of the orbital period is proportional to the cube of the orbital radius. Therefore, T 2 A R 3 A = T 2 B R 3 B . Therefore, T B T A = parenleftbigg R B R A parenrightbigg 3 / 2 = 2 3 / 2 = 8 . 003 10.0 points The force F exerted on the block pushes the block against the ceiling and at the same time accelerates the block to the right. Version 080 Midterm 02 Yao (58180) 2 m F a Find the kinetic friction between the block and the ceiling. 1. f k = ( F sin + mg ) 2. f k = mg 3. f k = F sin 4. f k = ( F sin mg ) correct Explanation: The net normal force which pushes against the ceiling is F sin mg . So the kinetic friction is f k = ( F sin mg ). 004 10.0 points When an automobile moves with constant ve- locity, the power developed is used to over- come the frictional forces exerted by the air and the road. If the engine develops 50 hp, what total frictional force acts on the car at 160 mph? One horsepower equals 746 W, and one mile is 1609 m. 1. 521.597 2. 205.781 3. 222.548 4. 238.444 5. 606.95 6. 1854.57 7. 1804.44 8. 513.573 9. 455.212 10. 596.111 Correct answer: 521 . 597 N. Explanation: Apply P = E t = Fd t = Fv F = P v = 50 hp 746 W hp 160 mph 1609 m mi h 3600 s = 521 . 597 N 005 10.0 points Pretend you are on a planet similar to Earth where the acceleration of gravity is approxi- mately 10 m / s 2 ....
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Traditional Old Midterm 2 - Version 080 Midterm 02 Yao...

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