Jennifer Lee2019W2MATH103ALLAssignment Assignment10 due 03/26/2020 at 01:00am PDT1.(1 point) Find the limit of the sequencean=(2n+1)!(2n-1)!.Ifthe limit does not exist, type ”Diverges” or ”D”.ity, state your answer as INF. If it diverges to negative infinity,state your answer as MINF. If it diverges without being infinityor negative infinity, state your answer as DIV.Limit:Answer(s) submitted:•D(correct)Correct Answers:•Diverges2.(1 point)Determine whether the sequence is divergent or convergent.If it is convergent, evaluate its limit. If it diverges to infinity,state your answer as INF. If it diverges to negative infinity, stateyour answer as MINF. If it diverges without being infinity ornegative infinity, state your answer as DIV.3.(1 point) If a sequencec1,c2,c3,...has limit K then thesequenceec1,ec2,ec3,...has limiteK.Use this fact together withc) If it is convergent, evaluate its limit. If it diverges to infin-ity, state your answer as INF. If it diverges to negative infinity,state your answer as MINF. If it diverges without being infinityor negative infinity, state your answer as DIV.limn→∞an=.Answer(s) submitted:•n/[(n+1)-(1/(n+1))]•convergent•1(correct)Correct Answers:

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l’Hopital’s rule to compute the limit of the sequence given bybn= (n)4.7n.N=Answer(s) submitted:•7(correct)6.(1 point)

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•14.(1 point)Supposea1=12-12,a2=23-13,a3=34-14,a4=45-15,a5=56-16.a) Find an explicit formula foran:.b) Determine whether the sequence is convergent or diver-gent:.Determine the limit of the sequence or show that the se-quence diverges by using the appropriate Limit Laws or theo-rems. If the sequence diverges, enter DIV as your answer.cn=ln2n-710n+4limn→∞cn=Solution:(Enter ”convergent” or ”divergent” as appropriate.)

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