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Unformatted text preview: Create assignment, 00223, Homework 4, Sep 15 at 9:06 pm 1 This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. Perpendicular Vectors 02 05:01, trigonometry, numeric, > 1 min, nor- mal. 001 Two vectors of magnitudes 10 N and 20 N act at right angles to each other. What is the magnitude of their resultant? Correct answer: 22 . 3607 N. Explanation: The resultant of two vectors acting at right angles to each other is the hypotenuse of a right triangle, so f = q f 2 1 + f 2 2 = q (10 N) 2 + (20 N) 2 = 22 . 3607 N Hanging Weight 04 05:07, trigonometry, numeric, > 1 min, wording-variable. 002 Consider the 700 N weight held by two cables shown below. The left-hand cable had tension T 2 and makes an angle of 2 with the ceiling. The right-hand cable had tension 570 N and makes an angle of 55 with the ceiling. The right-hand cable makes an angle of 55 with the ceiling and has a tension of 570 N . 700 N T 2 5 7 N 5 5 2 a) What is the tension T 2 in the left-hand cable slanted at an angle of 2 with respect to the wall? Correct answer: 401 . 518 N. Explanation: Observe the free-body diagram below. F 2 F 1 1 2 W g Note: The sum of the x- and y-components of F 1 , F 2 , and W g are equal to zero. Given : W g = 700 N , F 1 = 570 N , 1 = 55 , and 2 = 90 - . Basic Concept: Vertically and Horizontally, we have F x net = F x 1- F x 2 = 0 = F 1 cos 1- F 2 cos 2 = 0 (1) F y net = F y 1 + F y 2-W g = 0 = F 1 sin 1 + F 2 sin 2-W g = 0 (2) Solution: Using Eqs. 1 and 2, we have F x 2 = F 1 cos 1 (1) = (570 N)cos55 = 326 . 939 N , and F y 2 = F 3- F 1 sin 1 (2) = 700 N- (570 N)sin55 = 700 N- 466 . 917 N = 233 . 083 N , so F 2 = q ( F x 2 ) 2 + ( F y 2 ) 2 = q (326 . 939 N) 2 + (233 . 083 N) 2 = 401 . 518 N . Create assignment, 00223, Homework 4, Sep 15 at 9:06 pm 2 003 b) What is the angle 2 which the left-hand cable makes with respect to the ceiling? Correct answer: 35 . 4861 . Explanation: Using Eq. 2, we have 2 = arctan F y 1 F x 1 = arctan 466 . 917 N 326 . 939 N = 35 . 4861 . Three Forces 05:07, trigonometry, numeric, > 1 min, nor- mal. 004 An object in equilibrium has three forces ex- erted on it. A(n) 33 N force acts at 80 , and a(n) 44 N force acts at 60 . What is the direction of the third force? (Consider all angles to be measured counter- clockwise from the positive x-axis.) Correct answer: 248 . 557 ....
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This note was uploaded on 05/06/2011 for the course PHYS 103N taught by Professor Chiu during the Spring '11 term at University of Texas at Austin.

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2-4 - Create assignment, 00223, Homework 4, Sep 15 at 9:06...

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