Lecture 8 Outline - . Recombinant frequency = [(8 + 7)/(55...

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Bio 352 1 of 4 LECTURE 8 : Linkage and Recombination in Eukaryotes I Today’s topics : 1. Linkage and recombination 2. Mapping two genes 3. Mapping three genes from 2-point crosses 4. Biases from multiple crossovers Readings : Pierce, pgs. 161-170, 173-175 Mendel’s laws of segregation and independent assortment. 1. Segregation . 2. Independent assortment Recombination : Figure 7.2 Walter Sutton and the chromosome theory of heredity (1903) Violations of Mendel’s 2 nd Law – Figure 7.3 Linked genes and linkage groups Crossing over and recombination -- Figure 7.4. Notation: and OR and
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Bio 352 2 of 4 OR AB/AB and ab/ab F1 dihybrid: These representations are incorrect : and Complete linkage -- Figure 7.5a Independen t assortment -- Figure 7.5b Incomplete linkage -- Figure 7.6 Figure 7.7
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Unformatted text preview: . Recombinant frequency = [(8 + 7)/(55 + 53 + 8 + 7)] x 100%= 12.2% Bio 352 3 of 4 Genotype AaBb , we can have 2 possible arrangements for the alleles: or cis (= coupling ) configuration. trans (= repulsion ) configuration. Figure 7.8 Try Figure 7.10 in your spare time. two-point crosses Crossing over Chromosome mapping. distance inferred from recombination = map distance physical distance is the # base pairs is the physical distance Bio 352 4 of 4 map unit =1 centimorgan (cM) 1 cM = 1% recombination -- Map distance = (# recombinant gametes / total # gametes) X 100 Using a series of 2-point crosses for 3 linked construct a genetic map Next Time : Linkage and Recombination II (Lecture 9) Readings : Pierce, pgs. 175 179; 183...
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This note was uploaded on 05/07/2011 for the course BIOLOGY 352 taught by Professor Townsend during the Spring '08 term at San Diego State.

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Lecture 8 Outline - . Recombinant frequency = [(8 + 7)/(55...

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