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University of Texas CH 302 McCord H02 - Solutions 2

University of Texas CH 302 McCord H02 - Solutions 2 -...

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byrne (cmb3744) – H02: Solutions – mccord – (51620) 1 This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0points Dissociation of a solid is aided by 1. strong interaction between solvent molecules. 2. strong binding in the solid and weak solvent-solute interaction. 3. None of these is correct. 4. weak binding of species in the solid and strong interactions between the solvent and solute. correct Explanation: Weak intermolecular forces in the solute facilitate separation of its particles and strong attractive forces between solute and solvent facilitate dissociation of a solid. 002 10.0points Some distilled water is added to an empty beaker. A gram of copper(II) nitrate is added to the beaker with stirring. After a few min- utes, what is in the beaker? 1. solid copper, nitrate ions, and water 2. a sticky material of copper hydronitrite 3. solid copper(II) nitrate and water 4. nitrogen gas, copper atoms, electrons, and water 5. copper ions, nitrate ions, and water cor- rect Explanation: All nitrates are soluble in water, so the cop- per(II) nitrate dissolves. Soluble ionic com- pounds are strong electrolytes, so the cop- per(II) nitrate also dissociates into its cation and anion parts: Cu + 2 and NO 3 . 003 10.0points Both ammonia and phosphine (PH 3 ) are sol- uble in water. Which is least soluble and why? 1. ammonia; it is too small to be hydrated by water molecules. 2. ammonia; it does not form hydrogen bonds with water molecules. 3. phosphine; the P - H bonds are so strong that they cannot break to enable phosphine to hydrogen-bond with water. 4. phosphine; it does not form hydrogen bonds with water molecules. correct 5. ammonia; the N - H bonds are so strong that they cannot break to enable the ammonia to hydrogen-bond with water.
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