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University of Texas CH 302 McCord H10 - Solubility

# University of Texas CH 302 McCord H10 - Solubility -...

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byrne (cmb3744) – H10: Solubility – mccord – (51620) 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0points The compound M 2 X 3 has a molar solubility of 0.0280 M. What is the value of K sp for M 2 X 3 ? 1. 1 . 66 × 10 - 5 2. 6 . 2 × 10 - 7 3. 1 . 72 × 10 - 8 4. 0 . 000132 5. 1 . 86 × 10 - 6 correct Explanation: 002 10.0points A solution in equilibrium with solid barium phospate is found to have a barium ion con- centration of 5 × 10 - 4 mol/L and a K sp of 5 × 10 - 23 . Calculate the concentration of phosphate ion. 1. 3 . 16 × 10 - 10 mol/L 2. 4 . 64 × 10 - 7 mol/L 3. 6 . 32 × 10 - 7 mol/L correct 4. 5 . 77 × 10 - 11 mol/L 5. 2 . 50 × 10 - 64 mol/L Explanation: 003 10.0points Assume the molar solubility of silver chromate (Ag 2 CrO 4 ) is represented as x . Which of the following expressions correctly expresses the relationship between the molar solubility of silver chromate and the solubility product constant ( K sp ) for this compound? 1. K sp = 4 x 3 correct 2. K sp = x 2 3. K sp = 2 x 3 4. K sp = 4 x 2 5. K sp = 2 x 2 Explanation: The equation for the dissociation of Ag 2 CrO 4 is written as Ag 2 CrO 4 2 Ag + + CrO - 4 . The expression for K sp = bracketleftbig Ag + bracketrightbig 2 bracketleftbig CrO - 4 bracketrightbig . Since the molar solubility is x , K sp can be rewritten (in terms of x ) as K sp = [2 x ] 2 [ x ] = 4 x 3 . bracketleftbig Ag + bracketrightbig = 2 x because for every salt molecule that dissociates, 2 Ag + ions are produced. 004 10.0points Which of the following compounds has the LOWEST molar solubility in water?

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