Homework #13 Answers

Homework #13 Answers - Each correct name is worth 3 points...

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Graded Homework Assignment #13 – Answer Key Deadline : 9:00 a.m., Friday, 4/2/10 LATE WORK WILL NOT BE ACCEPTED OR GRADED!!! This assignment is worth a total of 40 raw points. In Questions 1 and 2, draw a line–angle structure that corresponds to the name given. In each structure that you draw, the stereochemistry needs to be shown clearly and unambiguously. Use wedges, dashed wedges, and normal lines where appropriate to show the stereochemistry. Only structures written in the boxes provided will be graded! 1. (4 points) cis -3-Heptene 2. (6 points) (2 E ,5 Z )-3,5-Dimethyl-2,5-octadiene In Questions 3 and 4, the names given are incorrect . Use the incorrect name to draw a line-angle structure in the top, larger box. Each line-angle structure is worth 4 points. Then, write the correct name of the compound in the small box that appears below the large box.
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Unformatted text preview: Each correct name is worth 3 points. 3. 2-Methyl-4-methylene-2-hexene 4. 1,6-Dimethyl-1,5-cyclohexadiene 2-Ethyl-4-methyl-1,3-pentadiene 2,3-Dimethyl-1,3-cyclohexadiene 2 5. (4 points) When methylenecyclopentane is exposed to HCl, a single, achiral product is formed. Please draw the structure of this product in the empty box below. 6. (12 points) In the space below, propose a mechanism for the reaction described above. Use curved arrows to show movement of electron pairs, and be sure to draw structures for all important reaction intermediates. If an intermediate is a resonance hybrid, please draw all important contributing resonance structures. For full credit, your mechanism needs to be consistent with the product you drew in your answer for Question 5! HCl Cl CH 3 H Cl H Cl Cl CH 3...
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Homework #13 Answers - Each correct name is worth 3 points...

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