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Unformatted text preview: ° ( 4 ) ´ ° ( 3 ) ´ ° ( 2 ) ´ ° ( 1 ) ´ 2 ° = ³ 3 Problem 7.4: Find the solution of the following initial value problem and the initial conditions. ³ 2 ° ′′ + 2 ³°µ ´ 6 ° = 0 ° (1) = 2 ° ′ (1) = 1 Problem 7.5: Solve the following system of equations with given initial conditions: ⎩ ⎨ ⎧ ³ ′ = ³ ´ 2 ° ° ′ = ³ ´ 4 ° ³ (0) = 2 ° (0) = 3...
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This note was uploaded on 05/09/2011 for the course AMS 361 taught by Professor Staff during the Spring '08 term at SUNY Stony Brook.
 Spring '08
 Staff

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