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Unformatted text preview: Salomon ke, Version 1. 1. A university has two campuses — a downtown campus and a suburban campus. A total
of 300 students from both campuses are surveyed. The following is a histogram of the
commute times (in minutes) from home to campus the students spend on a typical
weekday. relative frequency
0.00 0.05 0.10 0.15 0.20 0.25 0.30 0 20 40 60 80 100 Commute times (minutes) a) Describe the shape of the distribution of the commute times. [1 mark]
Blmodal (one peak a1. N15 and another at A 55)
and asymmetrical. b) Where does the mean commute time fall? Circle the most appropriate answer. [2
marks] @Below 50 minutes. B. Between 50 and 60 minutes.
C. Above 60 minutes. c) Where does the 40th percentile of the commute times fall? Circle the most ap
propriate answer. [2 marks]
A. Between 20 and 30 minutes.
B. Between 30 and 40 minutes.
© Between 40 and 50 minutes.
D. Between 50 and 60 minutes. d) We now look at the commute times for students going to the two campuses sep
arately. The following are sidebyside boxplots of the commute times. 40 60 80 100 commute time (minutes) 20 Dow town Sub rban
campus campus Which of the following statements is / are correct? Check all that apply. [4 marks] For students going to the downtown campus, the maximum commute time is
between 20 and 40 minutes. For students going to the downtown campus, the distribution of the commute
times is roughly symmteric. ‘/ The commute times of students going to the suburban campus have a larger
IQR than those of students going to the downtown campus. 1" Over 75% of students going to the suburban campus spend more than 40
minutes on commuting. _,_ None of the above. e) The sample of 300 students who are surveyed consists of a simple random sample
of 80 students drawn from the downtown campus and a simple random sample of
220 drawn from the suburban campus. Identify the population and the sampling
method used. [4 marks] Population: til} Students 0F ﬁne univerSity (99m boils mmPU565) Sampling method: StVQU'FIEKl random somplmg (CamPus ls 0.
stratum) 2. In the same survey, the 300 students are also asked if they take bus or drive to campus.
Among the 80 students going to the downtown campus, 48 take bus and 32 drive.
Among the 220 students going to the suburban campus, 132 take bus and 88 drive. a) A student is randomly chosen from the 300 students.
Deﬁne two events:
A = The student goes to the downtown campus.
B = The student drives. Are A, B independent events? Justify your answer. [4 marks] PU! and )
_§_° ,32+33 F IZO g PM and B) . ; P A = :OJOH _ 2Iz/mon z __9.
L and 8) ago ~— ”0/300 80/300 .. 1 _
PM” W5) 3:0“ 3%” = 31/t:zo ‘ 32/30 ; 0 I064 : 0.2%: 20.4 120 _ o _ _ __
=P£A nude) 1 PLA)‘;T.E, " Pm)" 300 l“! 5 are independent b) Two students are randomly chosen from the 300 students without replacement.
Given that both students drive, what is the probability that they go to different
campuses? Circle your answer. You need not Show any calculation. [2.5 marks] A. 0.0314 B. 0.0628
_ _3___2 x§——8 +§_g 3'2.—
0.0.1972 .0.3944 4"” no "T’Fq +r—zo K'F—u c) Five students are randomly chosen from the 300 students with replacement. What
is the probability that at least one drives to campus? Circle your answer. You
need not show any calculation. [2.5 marks] A Fit—33) (.1733) B1“(t38)5
©1  (i—33)5 13 (1  tit 5 P(u+ least 1 drum)
:l— P(none droves) Wail talc; bus) 42+132 s
300 ) _.. I 3. CleanSmile Corporation makes electric toothbrushes. The lifetimes of a model of elec
tric toothbrush manufactured by the company are normally distributed with mean
34 months and standard deviation 7 months. Any toothbrush that fails during the
warranty period will be replaced free by the company. a) How long should the warranty period be if the company does not want to replace
more than 2.5% of the toothbrushes? [4 marks] Answer: The warranty period is 20 1% months. Show your calculation: X : lifetime, 0’? 0. toothbrush m N(/u:3l+) 0: 3}) Toothbrush Will be. replaced if its lifetime X L5
Shorter than ﬂu. Warranty PQYIOd W
Le. P( X< w) : 0.025 26mm. For 0.) as 4.96 95 use es—qs—qqs mic ,0‘01"
0N2“, middle
w '15 280 below)» 06%
w=342C¥)=20 f b) Fill in the blanks. Give your answers in two decimal places. You need not Show
any calculation. [2 marks] The lifetimes of the electric toothbrushes in years will have mean 2'83 ﬁr and variance O‘aLl 3(1
+ 1‘ l
:f.
3* .2? Ti 5 4. In a factory, trainees are trained to operate a device to assemble a product. By the
end of a one—month training period, they will be hired if they successfully assemble 5
or more products Within an hour. Based on the existing training method, the number
of products that are assembled within an hour by a trainee after training, X, has this probability distribution: :0 2 3 4 5 6
P(X=:i:) 0.01 0.01 0.16 0.67 0.15 a) E(X) is computed to be 4.94. Interpret this value in the context of this question.
[2 marks] It we repeatedly observe the trainees, the long run
average oF #pmducts as5emb\ed Wlthln an hour bf)
mesa trainees Is LVN. b) What is the probability that in a random sample of 130 trainees, more than 80%
are hired at the end of the training period? You must use an approximation
method to solve this problem. State any assumptions you make in your calcula
tion. [6 marks] Y = # trainees who ave hired xv SM (n: I30, p: o.bs+o.ls I“ : O. 832)
p : sample pmpomon oF 150 T
trainees who Will be. hired Pmbabili'f'g 0p
, aS$€mblln3 25
Check cond moms  products L!) The Sample .5 random
<2) n=130< 5% or an trainees (this IS an assumPhOn)
(3) hp: 130(082) : mac 7 t0 3 nil—p): 15002.13): 23H+>lo Normal approx to A Normal a «M +0 Eamomial
a gamma”; m “We: mm,  P(Y> cameo) P( i} > 053) :PW >104) = P(Y.>_los)
__ P 30332. 5 0.15—0.82.) I PLY7 Ot+5)+— Continwty
* (o 035:} I 04333"? Comhm
_ _ 1406.6 104.5 [06.6
— Pl ‘z'é > “0 5‘1) “Pl 4.38047 453304)
2 —OZ‘—I~:Ho {,9 =PCE>ao as)
"‘7 0 422.4  //? A : —0
p I 305e, f
D% 0.31 2 0 6844+ C c) There is a new method for training workers to Operate the device. The training
manager plans to conduct a randomized block design experiment to compare the
new method with the existing method. He will block the experiment by the
handedness of the trainees. Since left handers operate the device differently from
right handers when assembling products, handedness may aﬁect productivity. The
incoming group of 100 trainees will participate in the experiment. i. Explain the purpose of blocking by handedness of the trainees. [2 marks] To ﬁllmmale the eFFecl 0F handedness On
wactmtg OF the. trainees When Comparing the.
1 training methods ii. What are the treatments? [3 marks] How many? _._7*___
List them all: 0) EXIShng trawling WHO“ (2') new training method iii. What is the response variable? Limit your answer to 10 words. [2 marks] ”the number 0i" products that are assembled
M'Hnm an hour by a trainee iv. Describe how the 100 trainees are assigned to the different treatments. 3
marks] The trainees awe First dlwded into 7_ groups 193
Mew handedness
UJPrhm each smup (block); the trainees one randomtzed +0 one 0F the 2 Ueahnmtx 5. In a city with over 500,000 registered vehicles, the costs of auto insurance of all regis
tered vehicles have a mean of $1423 and a standard deviation of $533.2. Sixty—ﬁve percent of all registered vehicles have auto insurance that costs over $1423. a) True or false? The distribution of auto insurance costs of all registered vehicles
is approximately Normal. [3 marks] Circle your answer: Time Justify your answer:
The dlStrlloutlon \5 not ngmCtnc ~ home than 50°13 0? Insurance. costs 0M. greater than the mean Hence the, distribution (1cm not be, Normal.
b) Sixteen registered vehicles are randomly chosen. What is the standard deviation of the total auto insurance costs of the 16 vehicles? Circle your answer. [2 marks]
A. $33325 B. $133.3 ©$2l328 D. 3385312 0) Sixteen registered vehicles are randomly chosen. The number of vehicles (out of
the 16 vehicles) that have auto insurance costing over $1423 will follow (circle
only one answer) [2.5 marks] A. approximately the Normal distribution with standard deviation gigs; B. approximately the Normal distribution with standard deviation 16(0.65) (1  0.65).
. . . . . . . 0.65 10.65 C. approximately the Normal distribution w1th standard dev1ation (I L—Xr—l. CD) the Binomial distribution with standard deviation (/16(0.65)(1 — 0.65). E. both (B) and (D).
F. both (C) and (D) d) Consider repeated random samples of 100 registered vehicles. The average auto
insurance cost of the 100 registered vehicles over these repeated samples will follow
(circle only one answer) [2.5 marks] A. a non—Normal distribution with standard deviation 533.2.
approximately the Normal distribution with standard deviation 5731?). C. approximately the Normal distribution with standard deviation 100(0.65)(1  0.65). D. approximately the Normal distribution with standard deviation (1 LEW—51. E. the Binomial distribution with standard deviation 100(0.65)(l — 0.65).
F. Both (C) and (E). ...
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 Spring '08
 KARIM

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