MAT_1143-may_2 - May 2, 2011 Click to edit Master subtitle...

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Click to edit Master subtitle style May 2, 2011 Section 8.3
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Exam 4 We are on schedule for Exam 4 to be Wednesday, May 11. It will cover Section 7.1-8.8 (the parts we cover)
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X-intercept From factored form easy to tell where quadratic = 0 to give the x-intercept Need to solve f(x) = 0. Or something like: x2 – 2x = 3 Two methods we’ll use: Factoring: try to write as (_x + _)(_x + _) Quadratic Formula: a ac b b x 2 4 2 - ± - =
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Solve x2 – 2x = 3 Subtract 3 from both sides to get x2 – 2x – 3 = 0 (x + )(x ) = 0 What would go in the blanks? A: 3, -1 B: -3, 1 C: 1, 3 D: -1, -3 So, factors to (x – 3) (x + 1) = 0 So solutions/roots are A: 3, 1 B: -3, -1 C: 3, -1 D: -3,1
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Intercepts Looked at y = 3x2 – 6x – 45 earlier Solve 3x2 – 6x – 45 = 0 Factor out the 3 and we get A: 3(x2 – 2x – 45) = 0B: 3(x2 – 2x – 15) = 0 C: 3(x2 – 6x – 45) = 0D: 3(3x2 – 2x – 15) = 0 3(x2 – 2x – 15) = 0, so we try to factor more
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MAT_1143-may_2 - May 2, 2011 Click to edit Master subtitle...

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