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Unformatted text preview: Problem: The top food snacks consumed by adults aged 1854 are gum, chocolate candy, fresh fr potato chips, breath mints/candy, ice cream, nuts, cookies, bars, yogurt, and crackers. O random sample of 25 men, 15 ranked fresh fruit in their top five snack choices. Out of a sample of 32 women, 22 ranked fresh fruit in their top five snack choices. Is there a diff in the proportion of men and women who rank fresh fruit in their top five list of snacks? (Data are from The NPD Group press release, Fruit #1 Snack Food Consumed by Kids June 16, 2005.) (a, b, c) Data: n1 25 (1) Formulate the hypotheses: (2) Decide the test statistic and the level of significance: 0.1 (3) State the decision Rule: Reject H0 if |z| > 1.6449 (4) Calculate the value of test statistic: Average proportion, p = (n1p1 + n2p2)/(n1 + n2) = 0.6491 q = 1 - p = 0.3509 0.13-0.6869 (5) Compare with the critical value and make a decision: Since 0.6869 Decision: There is no sufficient evidence of a significant diff (6) Calculate the p- value for the test and interpret it: p- value = 0.4922 (d)n1p1 = 15, n1(1 - p1) = 10, n2p2 = 22, n2(1 - p2) = 10 Since none of the above values is < 10, normality can be assumed....
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- Spring '11