Test 1 - P HYSICS 2102 STUDY GUIDE TEST 1 Electrical Force:...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
PHYSICS 2102 STUDY GUIDE TEST 1 : Electrical Force : [F e ]=N, [q]=C Coulomb’s Law = ( )( Fe k q1 ) q2 r2 : Electric Field of a Point Charge: [E]= NC = = E Feqt kqsr2 The Electric Field always points from positive to negative. Positive charges (protons) want to travel in the direction of the electric field, but negative charges (electrons) want to travel in the opposite direction. : Electric Field due to a Line of Charge: = = λ chargelength QL = dE kdqr2 where (small piece of charge on line) = dq λdl , , dl should be chosen dx dy or dsRdΘ based on the ( . . ) geometry of the line i e ds for a curve To solve for E, integrate both sides: = = dE ifkdqr2 ifkλdlr2 : Flux: [ Φ ]= Nm2C = = Φ E∙dA qencϵ0 If electric field is constant: = = Φ E∙A EAcosθ
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Gauss’ Law = = Φ E∙dA qencϵ0 , : = On a Gaussian surface the integral reduces to EA qencϵ0 : Spherical Symmetry: : = In a Gaussian Sphere E kqr2 Insulating Sphere: Linear: = = λ chargelength QL Surface: = = σ chargearea QA
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 5

Test 1 - P HYSICS 2102 STUDY GUIDE TEST 1 Electrical Force:...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online