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# Wk 5 - Lauren Sims MTH 210 April 4 2011 8.1 Planes and...

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Lauren Sims MTH 210 April 4, 2011 8.1 Planes and Polyhedrons 4. False 6. False 8. True 10. True 12. False 16. F = 14, V = 14, E = 26 14 + 14 – 26 28 – 26 = 2 28. The cube has 4 diagonals 8.2 Prism 4. SA = LA + 2B P = 4(5) P = 20 SA = 20(5) + 2(5) 2 SA = 100 + 50 SA = 150 ft 2 6. SA = LA + 2B

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P = 2(6) = 2(2) P = 12 + 4 P = 16 SA = 16(5) + 2(6)(2) SA = 80 + 24 SA = 104 ft 2 20. LA = ph P = 4 + 6 + 7 + 8 + 10 = 35 LA = 35(10) LA = 350 in 2 22. P = 4(5) = 20 B = 5 2 = 25 SA = 20(5) + 2(25) SA = 100 + 50 SA = 150 cm 2 V = 25(5) V = 125 cm 2 28. h 2 + 3 2 = 5 2 H 2 + 9 = 25 H 2 = 16 A = ½(2 + 8)(4) A = ½(10)(4) A = 40/2 A = 20 V = (20)(9/12)
V = 15 ft 3 8.3 Pyramids 6. P = 5(8) P = 40 AB = 10 so only one leg is 4 cm 4 2 + l 2 = 10 2 16 + l 2 = 100 L 2 = 84 L = square root of 84 SA = LA + B = 1/2pl + 1/2ap SA = ½(40)(square root of 84) + ½(5.5)(40) SA = 20 square root of 84 + 110 Surface area is approx. 293.3 cm 2 12. B = (30.6) 2 = 936.36 H 2 + (15.3) 2 = (46.8) 2 H 2 + 234.09 = 2190.24 H 2 = 1956.15 H = square root of 1956.15 V = 1/3(396.36)(square root of 1956.15) V = 312.12 square root of 1956.15 V = 13,804.6 Volume of the pyramid is approx. 13,804.6 ft 3 18. h 2 + 2 2 = 3 2 H 2 = 3 2 - 2 2 H 2 = 9 – 4

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H 2 = 5 H = square root of 5 V = 1/3(16) square root of 5 V = 11.9 The bottle of perfume will hold 11.9 cm 3 20. Missing side of smaller: 3 2 + 4 2 = c 2 9 + 16 = c2 25 = c 2 C= 5 Missing side of larger retia: 8 2 + b 2 = 10 2 64 + b 2 = 100 B 2 = 36 B = 6 The area of the two triangular base are: A 1 = ½(3)(4) A 1 = 12/2 A 1 = 6 A 2 = ½(6)(8) A 2 = 48/2 A 2 = 24

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Wk 5 - Lauren Sims MTH 210 April 4 2011 8.1 Planes and...

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