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marketing research ch 13 pt b

# marketing research ch 13 pt b - 3)Age mean = 509/11 = 46.27...

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Sarah Anderson Marketing Research Chapter 13 Pt B Part B (20 possible points) Case 13.1 (Page 349) All questions 1.) Calculate a mean and a standard deviation for each variable. Age mean = 509/11 = 46.27 age standard deviation = 14.59514 Years of experience mean = 50/11 = 4.545 or 4.55 experience standard deviation= 3.72461 Prev. yr. Mean = 7,879,417/11 = 716,310.63 prev. year standard deviation = 433954.60897 or 433954.61 current year mean = 8874596/11 = 806781.45 current year standard deviation = 560069.118 2.) Age mean = 509/11 = 46.27 confidence level = 8.63 Years of experience mean = 50/11 = 4.545 or 4.55 confidence level = 2.2 Prev. yr. Mean = 7,879,417/11 = 716,310.63 current year mean = 8874596/11 = 806781.45

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Unformatted text preview: 3.)Age mean = 509/11 = 46.27 Years of experience mean = 50/11 = 4.545 or 4.55 Prev. yr. Mean = 7,879,417/11 = 716,310.63 current year mean = 8874596/11 = 806781.45 Age mode: 64 yrs of experience mode: 2 prev year mode: no mode current year mode: no mode age median: 42 years of experience median: 3 prev. year median: 518,897 current year median: 519412 Current Year Previous Year 4.) Amount Frequency Frequency Under \$500,000 5 4 500,000-999,999 3 4 1,000,000 and over 3 2 Years Experience 5.) Classes _______________________________________Frequency Less than 5 years 6 More than 5 years 5 6.) 6/11 = .545 or .55 or 55% 5/11 = .454 = 45%...
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marketing research ch 13 pt b - 3)Age mean = 509/11 = 46.27...

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