p0164 - 6 a = 2 and a = 4 Therefore, the eccentricity is 6...

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1.64. CHAPTER 1, PROBLEM 64 71 1.64 Chapter 1, Problem 64 Problem: In Cartesian coordinates, the equation describing an ellipse is ( x +2) 2 / 16 + y 2 /b 2 =1 . Determine the ellipse’s eccentricity, 6 ,andthecons tan t b . Solution: The general equation for an ellipse is ( x + 6 a ) 2 a 2 + y 2 b 2
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Unformatted text preview: 6 a = 2 and a = 4 Therefore, the eccentricity is 6 = 6 a a = 1 2 For an ellipse, we know that a = 6 p 1 6 2 = 6 p = a D 1 6 2 i = 3 We also know that b = 6 p 1 6 2 = 1 2 3...
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