H12- Thermo 1-solutions

# H12- Thermo 1-solutions - patel (ap28872) – H12: Thermo 1...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: patel (ap28872) – H12: Thermo 1 – mccord – (51600) 1 This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points On January 1, 2001, a bookstore had 266,478 books in stock. On February 1, 2001, the same bookstore had 257,814 books in stock. What is the value of Δ(books) for the bookstore during that period? Correct answer: − 8664 books. Explanation: B f = 257 , 814 books B i = 266 , 478 books Δ B = B f − B i = 257 , 814 books − 266 , 478 books = − 8664 books Thus the bookstore had 8664 fewer books on February 1. 002 10.0 points Work is 1. chaotic molecular motion. 2. heat. 3. organized molecular motion. correct 4. potential energy. 5. kinetic energy. Explanation: Work is organized molecular motion since it is displacement of a solid against a force. 003 10.0 points A chemical reaction takes place in a container of cross-sectional area 100 cm 2 . As a result of the reaction, a piston is pushed out through 23 cm against an external pressure of 573 torr. What is the value for w for this reaction? (Sign does matter.) Correct answer: − 176 J. Explanation: 004 10.0 points A 100 W electric heater (1 W = 1 J / s) oper- ates for 9 min to heat the gas in a cylinder. At the same time, the gas expands from 5 L to 12 L against a constant atmospheric pressure of 4 . 053 atm. What is the change in internal energy of the gas? Correct answer: 51 . 1253 kJ. Explanation: P ext = 4 . 053 atm V ini = 5 L 1 L · atm = 101 . 325 J V final = 12 L If the heater operates as rated, then the to- tal amount of heat transferred to the cylinder will be q = (100 J / s) (9 min) (60 s / min) = 54000 J = 54 kJ Work will be given by w = − P ext Δ V in this case because it is an expansion against a constant opposing pressure: w = − (4 . 053 atm) (12 L − 5 L) = − 28 . 371 L · atm Convert to kilojoules (kJ) w = ( − 28 . 371 L · atm)(101 . 325J / L · atm) = − 2874 . 69 J = − 2 . 87469 kJ The internal energy change is Δ U = q + w = 54 kJ + ( − 2 . 87469 kJ) = 51 . 1253 kJ 005 10.0 points A system had 150 kJ of work done on it and its internal energy increased by 60 kJ. How much energy did the system gain or lose as heat? 1. The system lost 210 kJ of energy as heat. patel (ap28872) – H12: Thermo 1 – mccord – (51600) 2 2. The system lost 90 kJ of energy as heat. correct 3. The system gained 90 kJ of energy as heat. 4. The system gained 210 kJ of energy as heat. 5. The system gained 60 kJ of energy as heat. Explanation: Δ U = q + w q = Δ U − w = 60 kJ − (+150 kJ) = − 90 kJ (Negative means the system lost energy as heat.) 006 10.0 points When 2.00 kJ of energy is transferred as heat to nitrogen in a cylinder fitted with a piston at an external pressure of 2.00 atm, the nitro- gen gas expands from 2.00 to 5.00 L against this constant pressure. What is Δ U for the process?...
View Full Document

## This note was uploaded on 05/12/2011 for the course CH 301 taught by Professor Fakhreddine/lyon during the Spring '07 term at University of Texas.

### Page1 / 6

H12- Thermo 1-solutions - patel (ap28872) – H12: Thermo 1...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online