Exam 1-solutions - Version 357 Exam 1 mccord (51600) 1 This...

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Unformatted text preview: Version 357 Exam 1 mccord (51600) 1 This print-out should have 34 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points What is the maximum value that m can have for a 3 d orbital? 1. 2. 2 correct 3.- 3 4. 3 5.- 1 6.- 2 Explanation: m =- , ..., , ..., For a d orbital = 2 . 002 10.0 points Which is NOT true about light? 1. As the frequency of light increases, the wavelength decreases. 2. The energy of a photon is directly propor- tional to its wavelength. correct 3. It can behave like either particles or waves. 4. X-rays and visible light both travel at the same speed. Explanation: 003 10.0 points A 200 nm photon has how many times the energy of a 700 nm photon? 1. 2 . 84 10 19 2. 3.5 correct 3. 0.29 4. 0.24 5. 9 . 93 10 19 6. 4.2 Explanation: Energy of Light: E = hc For the 200 nm photon: E = hc = (6 . 626 10 34 J s)(3 10 8 m s 1 ) 200 10 9 m = 9 . 94 10 19 J For the 700 nm photon: E = hc = (6 . 626 10 34 J s)(3 10 8 m s 1 ) 700 10 9 m = 2 . 84 10 19 J Thus 9 . 94 10 19 J 2 . 84 10 19 J = 3 . 5 004 10.0 points Which response identifies a possible for the last-filled electron in a chloride ion? 1. 3 , , 2. 3 , 1 , 1 correct 3. 3 , 3 , 1 4. 2 , 1 , 2 5. 2 , , 6. 2 , , 1 Explanation: The are written in format n,,m . The electronic configuration for the chloride ion is Version 357 Exam 1 mccord (51600) 2 [Ne] 3 s 2 3 p 6 , so the last-filled electron is in 3 p . For the 3 p orbital, n = 3, = 1, and m can be- 1 , , +1. (The m can be any of those values because the orbitals are degenerate, so may fill in any order.) 005 10.0 points What is the frequency of light with a wave- length of 4.0 10 7 m? 1. 7 . 5 10 14 s 1 correct 2. 1 . 3 10 15 s 1 3. 3 . 10 14 s 1 4. 3 . 10 14 s 1 5. 120 s 1 Explanation: 006 10.0 points How many electrons can possess this set of quantum numbers: principal quantum number n = 4, magnetic quantum number m =- 1? 1. 10 2. 14 3. 4 4. 16 5. 8 6. 7. 2 8. 18 9. 12 10. 6 correct Explanation: Use the rules for the quantum numbers: If n = 4 then = 0 , 1 , 2 , 3; however, for m =- 1, = 1 , 2 , 3. Each of these permit- ted sets of values of n , and m specifies ONE orbital: n = 4, = 1, m =- 1: 4 p n = 4, = 2, m =- 1: 4 d n = 4, = 3, m =- 1: 4 f and each orbital can have m s = 1 2 ; i.e. , can hold two electrons. 007 10.0 points We conduct an experiment by shining 500 nm light on potassium metal. This causes electrons to be emitted from the surface via the photoelectric effect. Now we change our source light to 450 nm at the same intensity level. Which of the following is the result from the 450 nm light source compared to the 500 nm source?...
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This note was uploaded on 05/12/2011 for the course CH 301 taught by Professor Fakhreddine/lyon during the Spring '07 term at University of Texas at Austin.

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Exam 1-solutions - Version 357 Exam 1 mccord (51600) 1 This...

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