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Exam 1-solutions - Version 357 Exam 1 mccord(51600 This...

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Version 357 – Exam 1 – mccord – (51600) 1 This print-out should have 34 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0points What is the maximum value that m can have for a 3 d orbital? 1. 0 2. 2 correct 3. - 3 4. 3 5. - 1 6. - 2 Explanation: m = - ℓ,..., 0 ,...,ℓ For a d orbital = 2 . 002 10.0points Which is NOT true about light? 1. As the frequency of light increases, the wavelength decreases. 2. The energy of a photon is directly propor- tional to its wavelength. correct 3. It can behave like either particles or waves. 4. X-rays and visible light both travel at the same speed. Explanation: 003 10.0points A 200 nm photon has how many times the energy of a 700 nm photon? 1. 2 . 84 × 10 19 2. 3.5 correct 3. 0.29 4. 0.24 5. 9 . 93 × 10 19 6. 4.2 Explanation: Energy of Light: E = hc λ Forthe200nmphoton: E = hc λ = (6 . 626 × 10 34 J · s)(3 × 10 8 m · s 1 ) 200 × 10 9 m = 9 . 94 × 10 19 J Forthe700nmphoton: E = hc λ = (6 . 626 × 10 34 J · s)(3 × 10 8 m · s 1 ) 700 × 10 9 m = 2 . 84 × 10 19 J Thus 9 . 94 × 10 19 J 2 . 84 × 10 19 J = 3 . 5 004 10.0points Which response identifies a possible ψ for the last-filled electron in a chloride ion? 1. ψ 3 , 0 , 0 2. ψ 3 , 1 , 1 correct 3. ψ 3 , 3 , 1 4. ψ 2 , 1 , 2 5. ψ 2 , 0 , 0 6. ψ 2 , 0 , 1 Explanation: The ψ are written in format ψ n,ℓ,m . The electronic configuration for the chloride ion is
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Version 357 – Exam 1 – mccord – (51600) 2 [Ne] 3 s 2 3 p 6 , so the last-filled electron is in 3 p . For the 3 p orbital, n = 3, = 1, and m can be - 1 , 0 , +1. (The m can be any of those values because the orbitals are degenerate, so may fill in any order.) 005 10.0points What is the frequency of light with a wave- length of 4.0 × 10 7 m? 1. 7 . 5 × 10 14 s 1 correct 2. 1 . 3 × 10 15 s 1 3. 3 . 0 × 10 14 s 1 4. 3 . 0 × 10 14 s 1 5. 120 s 1 Explanation: 006 10.0points How many electrons can possess this set of quantum numbers: principal quantum number n = 4, magnetic quantum number m = - 1? 1. 10 2. 14 3. 4 4. 16 5. 8 6. 0 7. 2 8. 18 9. 12 10. 6 correct Explanation: Use the rules for the quantum numbers: If n = 4 then = 0 , 1 , 2 , 3; however, for m = - 1, = 1 , 2 , 3. Each of these permit- ted sets of values of n , and m specifies ONE orbital: n = 4, = 1, m = - 1: 4 p n = 4, = 2, m = - 1: 4 d n = 4, = 3, m = - 1: 4 f and each orbital can have m s = ± 1 2 ; i.e. , can hold two electrons. 007 10.0points We conduct an experiment by shining 500 nm light on potassium metal. This causes electrons to be emitted from the surface via the photoelectric effect. Now we change our source light to 450 nm at the same intensity level. Which of the following is the result from the 450 nm light source compared to the 500 nm source? 1. More electrons would be emitted from the surface. 2. No electrons would be emitted from the surface. 3. The same number of electrons would be emitted, but they would have a higher velocity correct 4. The same number of electrons would be emitted, but they would have a lower velocity 5. Fewer electrons would be emitted from the surface.
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